Question

Calculate the concentration of a 220 g solution of calcium chloride (CaCl2) that has a volume of 11 L

Answer 1

Answer: The concentration of the solution is 0.18 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

moles of $CaCl_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{220g}{111g/mol}=1.98mol$

Now put all the given values in the formula of molality, we get

$Molarity=\frac{1.98mol}{11L}=0.18M$

Therefore, the concentration of the solution is 0.18 M