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sattari [20]
3 years ago
14

Are there other universes?

Chemistry
1 answer:
____ [38]3 years ago
8 0
Our universe<span> may be one of many, physicists say. The </span>universe<span> we live in may not be the only one out </span><span>there</span>
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What best describes the goals of scientific investigation and technological development?
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Hi! I think the answer is option B. I hope
this helps, Goodluck :)
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How many more electrons are there in the last energy level of phosphorus, atomic
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3 years ago
(15 PTS) What are two parts of the atomic theory of atoms?
AnnZ [28]

1) All matter is made of atoms. 2) Atoms are indivisible and indestructible.

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3 years ago
Read 2 more answers
Consider the fermentation reaction of glucose: C6H12O6 → 2C2H5OH + 2CO2 A 1.00-mol sample of C6H12O6 was placed in a vat with 10
inessss [21]

Answer:

% yield = 73.48 %

Explanation:

The fermentation reaction is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂          

The percent yield of C₂H₅OH is given by:

\% yield = \frac{m_{E}}{m_{T}} * 100

<em>where m_{E}: is the obtained mass of C₂H₅OH = 67.7g and m_{T}: is the theoretical mass of C₂H₅OH.     </em>

The theoretical mass of C₂H₅OH is calculated knowing that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH:  

m_{T} = mol * M

<em>where M: is the molar mass of C₂H₅OH =  46.068 g/mol</em>

m_{T} = 2 moles * 46.068 g/mol = 92.136 g                

Hence, the percent yield of C₂H₅OH is:

\% yield = \frac{67.7 g}{92.136 g}*100 = 73.48 \%

I hope it helps you!                  

3 0
3 years ago
HELPPP!!! What is the volume of a 1.31 moles sample of gas if the pressure is 904 mmHg and the temperature is 37. degrees Celsiu
Tju [1.3M]

Answer:

27.99 dm³

Explanation:

Applying

PV = nRT................ Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

From the question, we were aksed to find V.

Therefore we make V the subject of the equation

V = nRT/P................ Equation 2

Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

V = (1.31×310×0.082)/(1.1897)

V = 27.99 dm³

4 0
3 years ago
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