Question

If 2.1 moles of NaCl is dissolved in a solution with a total volume of 7.3 liters, what is the molarity of the solution? Round to two decimals.

Answer 1

Answer:

M = 0.29 M

Explanation:

We are given;

Number of moles of NaCl; n = 2.1 moles

Total volume of solution; V = 7.3 L

Formula for molarity is;

M = n/L

Thus;

M = 2.1/7.3

M = 0.2878 M

Approximating to 2 decimal places gives;

M = 0.29 M

Answer 2

Answer:

The molarity of the solution is 0.29 $\frac{moles}{liter}$

Explanation:

Molarity, or molar concentration, is a measure of the concentration of a solute in a solution, be it some molecular, ionic or atomic species. It is defined as the number of moles of solute that are dissolved in a given volume.

Molarity is calculated as the quotient between the number of moles of solutes and the volume of the solution:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$.

In this case:

• number of moles of solute= 2.1 moles
• volume= 7.3 liters

Replacing:

$Molarity=\frac{2.1 moles}{7.3 liters}$

Molarity= 0.29 $\frac{moles}{liter}$

The molarity of the solution is 0.29 $\frac{moles}{liter}$