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vitfil [10]
3 years ago
10

If 2.1 moles of NaCl is dissolved in a solution with a total volume of 7.3 liters, what is the molarity of the solution? Round t

o two decimals.
Chemistry
2 answers:
finlep [7]3 years ago
7 0

Answer:

M = 0.29 M

Explanation:

We are given;

Number of moles of NaCl; n = 2.1 moles

Total volume of solution; V = 7.3 L

Formula for molarity is;

M = n/L

Thus;

M = 2.1/7.3

M = 0.2878 M

Approximating to 2 decimal places gives;

M = 0.29 M

Arturiano [62]3 years ago
5 0

Answer:

The molarity of the solution is 0.29 \frac{moles}{liter}

Explanation:

Molarity, or molar concentration, is a measure of the concentration of a solute in a solution, be it some molecular, ionic or atomic species. It is defined as the number of moles of solute that are dissolved in a given volume.

Molarity is calculated as the quotient between the number of moles of solutes and the volume of the solution:

Molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}.

In this case:

  • number of moles of solute= 2.1 moles
  • volume= 7.3 liters

Replacing:

Molarity=\frac{2.1 moles}{7.3 liters}

Molarity= 0.29 \frac{moles}{liter}

<u><em>The molarity of the solution is 0.29 </em></u>\frac{moles}{liter}<u><em></em></u>

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