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horsena [70]
3 years ago
6

Write a function to represent the set of ordered pairs for {(2, 2), (3, 7), (4, 14), (5, 23)}

Mathematics
2 answers:
weeeeeb [17]3 years ago
5 0
(x, x^{2}-2)


so, y=x^{2} -2 is the function
zlopas [31]3 years ago
5 0
A function that could work for this set of ordered pairs is f(x)=x^2-2.
If we look at each ordered pair, they fit this pattern.
2^2-2=4-2=2
3^2-2=9-2=7
4^2-2=16-2=14
5^2-2=25-2=23
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C. 65 degrees is the answer.
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4 years ago
What is the answer to m diveded by 8-7=12
lesya [120]
<span>We simplify the equation to the form, which is simple to understand
<span>m/8-7=12

</span></span><span>Simplifying:
<span> + 0.125m-7=12

</span></span><span>We move all terms containing m to the left and all other terms to the right.
<span> + 0.125m=+12+7

We simplify left and right side of the equation.
<span> + 0.125m=+19

We divide both sides of the equation by 0.125 to get m.
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7 0
3 years ago
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6 0
3 years ago
Solve the following quadratic-linear system of equations. y=x^2-x-6 and y=2x-2
Keith_Richards [23]

You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)

8 0
3 years ago
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What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Karo-lina-s [1.5K]

Let us find the co ordinates of each vertex of the triangle .

Vertex A ( in firs second quadrant) = ( -5 ,3)

vertex B in third quadrant = ( -5, -5)

vertex C in fourth quadrant = ( 4, -2)

let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0

AB= 8

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AC= 10.29

Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77

8 0
3 years ago
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