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KonstantinChe [14]
3 years ago
7

Calculate the solubility in mol/L of Lead(II) carbonate (PbCO3) at 298 K.

Chemistry
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

2.7x10⁻⁷mol/L

Explanation:

Based on the equilbrium:

PbCO₃(s) ⇄ Pb²⁺(aq) + CO₃²⁻(aq)

The solubility product, Ksp, is defined as:

Ksp = 7.4x10⁻¹⁴ = [Pb²⁺] [CO₃²⁻]

Now, solubility is defined as the amount of PbCO₃ that is dissolved, that is the concentration of the ions. Thus:

Solubility = S = [Pb²⁺] = [CO₃²⁻]

Replacing:

7.4x10⁻¹⁴ = [S] [S]

7.4x10⁻¹⁴ = [S]²

S = 2.7x10⁻⁷mol/L

You might be interested in
Estimate the coordination number for the cations in each of these ceramic oxides and also the coordination numbers of the oxygen
Juli2301 [7.4K]

Answer:

CN cation, anion ] respectively are thus [6,4] , [2,3] ,[6,6] , [6,6] , [6,3] , [12,6,2] , [6], [6].

Explanation:

The coordination number CN is the number of ligand atoms bonded (coordinate bonds) directly to the central of the metal ion. It is not the same as the oxidation state of the metal ion or complex.

Coordination number – the number of anions surrounding the cation.

In solving for CN we need to understand Pauling's rules.

According to Linus Pauling, 1932

“Pauling’s rules” for crystal structures, makes assumptions for ionic bonding. It states that ionic structure is understood using electrostatic rules of attraction and repulsion.

Cations and anions surround each other to neutralize charge – and these one can rationalize crystal structure with coordination number.

Ratio of cationic/anionic radius

• The structure of D-Al2O3 results in coordination number of 6 and 4 for cation and anion respectively.

• The average oxygen coordination number in v-B2O3 is equal to the average cation coordination number × cation/anion ratio (2/3).

• Co-ordination number of Ca2+ ion is =6;

In CaO crystal, Ca2+ is a cation and O2- is an anion. Cationic (Ca2+) has radius 100 pm and anionic (O2-) has radius  145 pm.

Ratio of cationic/anionic radius is:

r⁺/r⁻ = 100 / 145

r⁺/r⁻ = 0.69

CaO will form FCC lattice.

Coordination number in FCC lattice is 6. Therefore CN of Ca2+ = 6.

For MgO:

r Mg2+/ r O2- = 86pm / 126 pm =0.683

The cordination number for the cation is 6. MgO with ions Mg+2 and O-2 will have a AX type stochiometry exhibiting the

crystal structure of sodium chloride.

For TiO2:

The CN of the titanium (IV) cation is 6, which is twice the CN of the oxide anion, which is 3.

This fits with the formula unit of TiO2, since there are twice as many O2− ions as Ti4+ ions.

Consequently the crystal structure of all ionic compounds reflects the formula unit.

For LaAlO3 a Cubic perovskites (ABX3)

In perovskite structures, B cations are coordinated by six X anions, while A

cations present CN = 12 (also coordinated by X anions). The X anions have CN = 2, being

coordinated by two A cations, since the distance A-O is about 40% larger than the B-O

bond distance. The correct ionic radii (rA, rB, rX), taken from one of Shannon’s work.

rA = 1.36 pm

rB = 0.535 pm

rX = 1.35 pm

Forsterite Mg2SiO4

We have mixed sites of Si4+ in tetrahedral site, Mg2+ in octahedral site, O atoms anions .

They all forms octahedral chains/strips. The CN is estimated to (6) octahedral, with an average ratio 0.414

Nickel Cobaltite Ni(Co2O4)3

bidentate ligand includes the Oxalate, three oxalate ligands form six-coordinate bonds around the Ni2+ ion.

Co-ordinate number of Nickel in [Ni(C2​O4​)3​] 4− is 3×2=6.

5 0
3 years ago
Which of the following is an example of point-source pollution? A. Salt from roads B. Water from a sewage treatment plant C. Fer
ivanzaharov [21]

Answer:

Acid from abandoned mines- D.

7 0
3 years ago
A hot lump of 30.5 g of iron at an initial temperature of 52.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to r
slava [35]

Answer:

26.7°C

Explanation:

Using the formula; Q = m × c × ΔT

Where; Q = amount of heat

m = mass

c = specific heat

ΔT = change in temperature

In this question involving iron placed into water, the Qwater = Qiron

For water; m= 50g, c = 4.18 J/g°C, Initial temp= 25°C, final temp=?

For iron; m = 30.5g, c = 0.449J/g°C, Initial temp= 52.7°C, final temp=?

Qwater = -(Qiron)

m × c × ΔT (water) =- {m × c × ΔT (iron)}

50 × 4.18 × (T - 25) = - {30.5 × 0.449 × (T - 52.7)}

209 (T - 25) = - {13.6945 (T - 52.7)}

209T - 5225 = -13.6945T + 721.7

209T + 13.6945T = 5225 + 721.7

222.6945T = 5946.7

T = 5946.7/222.6945

T = 26.7

Hence, the final temperature of water and iron is 26.7°C

8 0
3 years ago
What is the pH of a solution has a hydrogen ion concentration of 6.3 x 10–10 M? Show work
NISA [10]

Answer:

pOH = 4.8

pH = 9.2

Explanation:

Given data:

Hydrogen ion concentration = 6.3×10⁻¹⁰M

pH of solution = ?

pOH of solution = ?

Solution:

Formula:

pH = -log [H⁺]

[H⁺] = Hydrogen ion concentration

We will put the values in formula to calculate the pH.

pH = -log [6.3×10⁻¹⁰]

pH = 9.2

To calculate the pOH:

pH + pOH = 14

We will rearrange this equation.

pOH = 14 - pH

now we will put the values of pH.

pOH = 14 - 9.2

pOH = 4.8

7 0
3 years ago
Which term describes rocks that absorb water?
KIM [24]

Answer:

C. porous

hope it helps!!!

please mark as the brainliest if it is correct!

8 0
3 years ago
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