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balu736 [363]
3 years ago
7

A student conducts an experiment by placing a wooden stick in a cup of sugar solution. Over the next few weeks, sugar crystals f

orm on the stick and increase in size. The student concludes that the resulting crystals must be alive because they grow.
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer: In order to be alive there must be cells present and since sugar does not contain cells it is not alive.

Explanation:

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Acetic acid is the active ingredient in vinegar. In a solution of acetic acid the following equilibrium is established. HC2H3O2(
lana [24]

Answer:

the equilibrium constant is 1.8 x 10⁻5 and strongly favor the reactants.

Explanation:

the chemical reaction provided for the two equation are the same but different direction i.e a reversible reaction. Assuming, the mass of reactants and product and temperature remain constant.

therefore, the equilibrium constant K, is 1.8 x 10⁻5. this is a very small value of K, thereby strongly favor the backward direction to form reactant.

6 0
4 years ago
"At constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature." This is -
Lostsunrise [7]

Answer: B

Explanation:

According to Charle's law, at constant pressure the volume of a fixed mass of a ga is directly proportional to its absolute temperature.

At constant pressure, V∝T.

6 0
3 years ago
What are the special characteristics of chromium, iron , titanium and manganese​
adoni [48]

Answer:

The two most useful properties of titanium include its resistance to corrosion and its high strength-to-weight ratio.

Chromium metal is highly valuable due to its high corrosion resistance and hardness.

Manganese is a metal with important industrial metal alloy uses, particularly in stainless steels.

Explanation:

7 0
3 years ago
a) Provide equation of K of this reaction, use symbol " ^ " for exponents. That means 1000 = 10^3 and 1/100 is 10^(-2). b) How m
stealth61 [152]

Answer and Explanation:

a. The equation of K of this reaction is shown below:-

3 A + 5 B + 4 C↔5 D + 7 E + F

K = \frac{(D)^5 (E)^7 (F)}{(A)^3 (B)^5 (C)^4}

b. The moles of compound F is shown below:-

3 A + 5 B + 4 C↔5 D + 7 E + F

               2 moles

Now, the mole of produced is

= \frac{1}{4} \times \ moles\ of\ c

Now, we will the value of c by using the above equation

= \frac{1}{4} \times 2

After solving the above equation we will get

0.5 moles

5 0
3 years ago
12. In a gas mixture consisting of carbon dioxide (CO2) and nitrogen (N2), the carbon dioxide molecules have a root-mean-square
zaharov [31]

Answer:

The correct answer is option e.

Explanation:

The formula used for root mean square speed is:

\nu_{rms}=\sqrt{\frac{3kN_AT}{M}}

where,

\nu_{rms} = root mean square speed

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature

M = Molar mass

N_A = Avogadro’s number = 6.02\times 10^{23}mol^{-1}

Root mean square speed of  carbon dioxide molecule:

\nu_{rms}= 550 m/s

Temperature of the mixture = T =?

Molar mass of carbon dioxide = 44 g/mol = 0.044 kg/mol

\nu_{rms}=550 m/s=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}T}{0.044 kg/mol}}

T = 533.87 K

Root mean square speed of nitrogen  molecule:

\nu'_{rms}= ?s

Molar mass of nitrogen = 28 g/mol = 0.028 kg/mol

\nu'_{rms}=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}\times 533.87 K}{0.028 kg/mol}}

\nu'_{rms}=689.46 m/s\approx 689 m/s

689 m/s is the root-mean-square speed of the nitrogen molecules in the sample.

7 0
3 years ago
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