Answer:
B and D
Explanation:
Because its adaptions they need to survive in the cold.
Answer:
In order to prepare 200.0 mL of an aqueous solution of iron (III) chloride, at a concentration of 1.25 x 10⁻² M, you need to weight 0.4055 g of FeCl₃ and add to 200.0 mL of water.
Explanation:
Concentration: 1.25 x 10⁻² M
1,25 x 10⁻² mol FeCl₃ ___ 1000 mL
x ___ 200.0 mL
x = 2.5 x 10⁻³ mol FeCl₃
Mass of FeCl₃:
1 mol FeCl₃ _____________ 162.2 g
2.5 x 10⁻³ mol FeCl₃ _______ y
y = 0.4055 g FeCl₃
In the given examples, Cl2 and CCl4 are non-polar and held by covalent bonds. HI and H2O are polar molecules and held by ionic bonds.
Since covalent bonds are weaker than ionic bonds, Cl2 or CCl4 must have the lowest melting points. Among the two, Cl2 has a lower molecular mass than CCl4, hence Cl2 must have the lowest melting point.
Ans A) Cl2
It’s really any metal because metals form metallic bonds. They are the only substances which can make metallic bonds. So the answer is A
Answer:
1.15 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 55.6 g
Volume (V) = 48.5 mL
Density (D) =?
Density is simply defined as the mass of the substance per unit volume of the substance. It is represented mathematically as:
Density (D) = mass (m) /volume (V)
D = m/V
With the above formula, we can obtain the density of the object as follow:
Mass (m) = 55.6 g
Volume (V) = 48.5 mL
Density (D) =?
D = m/V
D = 55.6/48.5
D = 1.15 g/mL
Therefore, the density of the object is 1.15 g/mL
