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Drupady [299]
3 years ago
12

Based upon the following equation: P4 + 5 O2 --> 2 P2O5 How many grams of P4 (molar mass 124 g = 1 mole) are necessary to rea

ct with 6.8 grams of O2 (molar mass 32 g = 1 mole)?
Chemistry
1 answer:
choli [55]3 years ago
4 0
Sorry I don't know this
You might be interested in
Drag each item to indicate whether it is related to Aristotle's or Ptolemy's model of the solar system, or to both. Some items m
Romashka-Z-Leto [24]

Answer:

<u>Aristotle's Model :</u>

geocentric

planets fixed on nested spheres

<u></u>

<u>Ptolemy's model:</u>

geocentric

planets fixed on epicycles

accurately predicted the positions of the planets

Explanation:

Let's begin by the fact both models are geocentric  and make a brief explanation of them:

<u></u>

<u>Aristotle's Model :</u>

Aristotle built his model based on observations and philosophical assumptions, not on measurements or calculations, then he mistakenly thought the Earth was the center of the universe.

So, according to this model, the universe was spherical and finite, with the Earth immobile at its center, composed of the four fundamental elements (made up of spherical layers): <em>ground, water, air and fire</em>; and the Sun along with the fixed planets in their respective concentric spheres (also called nested spheres) revolving around the Earth.

<u>Ptolemy's model:</u>

Ptolemy's model of the universe was also geocentric, placing the Earth motionless in the center of the known universe and was the accepted model for a long time during the Middle Ages.

In this sense, ccording to Ptolemy's model of the universe our planet remains stationary while the other planets, the Moon and the Sun describe complicated orbits around it (called epicycles).

However, this model predicted with an acceptable accuracy for that time the motion of the known planets, until Copernicus appeared with the revolutionary Heliocentric model.

5 0
3 years ago
At a pressure of 19.95kPa, 35.8g of carbon dioxide at a temperature of 27.5C would result in what volume of gas?
adell [148]

Answer:

volume of gas=101.94L

Explanation:

Suppose given gas follows the ideality nature of gas

PV=nRT

n=35.8/44mol=0.814 mol

P=0.197atm

T=27.5C=300.5K

R=0.0821atm/mol/K

after putting all value we get,

V=101.94L

volume of gas=101.94L

3 0
3 years ago
4 A Small rock
vodomira [7]

3 millimeters is the rock

6 0
3 years ago
Titanium is a transition metal used in many alloys because it is extremely strong and lightweight. Titanium tetrachloride (TiCl4
vova2212 [387]

Answer:

a) 226.6 grams of Cl₂

b) 19.2 grams of C

c) 303.2 grams of TiCl₄ and 70.4 grams of CO₂

Explanation:

The balanced chemical reaction is the following:

TiO₂(s) + C(s) + 2 Cl₂(g) → TiCl₄(s) + CO₂(g)

(a) What mass of Cl₂ gas is needed to react with 1.60 mol TiO₂?

From the chemical equation, 1 mol of TiO₂ reacts with 2 moles of Cl₂. So, the stoichiometric ratio is 2 mol Cl₂/1 mol TiO₂. We multiply this ratio by the moles of TiO₂ we have to calculate the moles of Cl₂ we need:

1.60 mol TiO₂ x 2 mol Cl₂/1 mol TiO₂ = 3.2 mol Cl₂

Now, we convert from moles to mass by using the molecular weight (MW) of Cl₂:

MW(Cl₂) = 35.4 g/mol x 2 = 70.8 g/mol

mass of Cl₂= 3.2 mol x 70.8 g/mol = 226.6 g

<em>Therefore, 226.6 grams of Cl₂ are needed to react with 1.6 mol of TiO₂. </em>

(b) What mass of C is needed to react with 1.60 mol of TiO₂?

From the chemical equation, 1 mol of TiO₂ reacts with 1 moles of C(s). So, the stoichiometric ratio is 1 mol C/1 mol TiO₂. We multiply this ratio by the moles of TiO₂ we have to calculate the moles of C(s) we need:

1.60 mol TiO₂ x 1 mol C(s)/1 mol TiO₂ = 1.60 mol C(s)

So, we convert the moles of C(s) to grams as follows:

MW(C) = 12 g/mol

1.60 mol x 12 g/mol = 19.2 g C(s)

<em>Therefore, a mass of 19.2 grams of C is needed to react with 1.60 mol of TiO₂. </em>

(c) What is the mass of all the products formed by reaction with 1.60 mol of TiO₂?

From the chemical equation, we can notice that 1 mol of TiO₂ produces 1 mol of TiCl₄ and 1 mol of CO₂. So, from 1.60 moles of TiO₂, 1 mol of each product will be produced:

1 mol TiO₂/1 mol TiCl₄ ⇒ 1.60 mol TiO₂/1.60 mol TiCl₄

1 mol TiO₂/1 mol CO₂ ⇒ 1.60 mol TiO₂/1.60 mol CO₂

Finally, we convert the moles to grams by using the molecular weight of each compound:

MW(TiCl₄) = 47.9 g/mol Ti + (35.4 g/mol x 4 Cl) = 189.5 g/mol

1.60 mol x 189.5 g/mol = 303.2 g

MW(CO₂) = 12 g/mol C + (16 g/mol x 2 O) = 44 g/mol

1.60 mol x 44 g/mol = 70.4 g

<em>Therefore, from the reaction of 1.60 mol of TiO₂ are formed 303.2 grams of TiCl₄ and 70.4 grams of CO₂.</em>

3 0
3 years ago
The acidity of normal rain water is due to ______.<br><br> a) SO2<br> b) CO2<br> c) NO2<br> d) NO
Viktor [21]

The correct answer choice is CO₂ (B)

Rainwater naturally contains acids derived from carbon dioxide in the air and reacts with water vapor to form weak acids

H₂O + CO₂ ---> H₂CO₃

<h3><em>Further Explanation</em></h3>

Rainwater can cause damage to buildings, animals or plants due to acid rain

Acid rain occurs because other gases in the air mix with toxic gases to form acids

Rainwater naturally contains acids derived from carbon dioxide in the air and reacts with water vapor to form weak acids

H₂O + CO₂ ---> H₂CO₃

However, due to exhaust gases from industry, motor vehicles, or power plants that use fossil fuels containing sulfur to produce sulfur dioxide gas which will produce sulfuric acid

Sulfur combustion from fossil fuels

S + O₂ ----> SO₂

SO₂ produced from this exhaust gas reacts with O₂ oxygen which oxidizes SO₂ to SO₃

SO₂ + O₂ ----> SO₃

SO3 formed reacts with water vapor in the air to produce sulfuric acid as acid rain

SO₃ + H₂O ---> H₂SO₄

To reduce the pollution from this fossil fuel, various studies are now carried out as substitute energy that is more environmentally friendly such as solar energy and so on

<h3><em>Learn more </em></h3>

Acid rain is a secondary pollutant

brainly.com/question/1324440

The impact of from acid rain

brainly.com/question/8208861

Air pollution

brainly.com/question/1232950

Keywords: acid rain, air pollution, SO₃, H₂SO₄, fossil fuel

6 0
3 years ago
Read 2 more answers
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