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3 years ago

Unless otherwise instructed, you may use the periodic table in the Chemistry: Problems and Solutions book for this question.

Chemistry

1 answer:

Aleks [24]3 years ago

8 0

Answer:

The electronegativity differences between carbon and oxygen are not very large.

Explanation:

Between the atoms of carbon monoxide exists a covalent bond which attaches the carbon to the oxygen.

In this type of bonding, both atoms shares a given number of valence electrons to attain chemical stability.

A substance is polar when there is a distinct charge separation between the species.

For covalent bonds, the electronegativity difference plays in important role in determining the polarity of the compound. When the difference is large, the compound will be polar but when the difference is very small or zero, no polarity will exist.

In between carbon and oxygen of carbon monoxide, the electronegativity difference is very low.

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The decomposition of hydrogen peroxide was studied, and the following data were obtained at a particular temperature: Time (s) (

harina [27]

Answer:

Part a: The rate of the equation for 1st order reaction is given as $Rate=k[H_2O_2]$

Part b: The integrated Rate Law is given as $[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c: The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d: Concentration after 4000 s is 0.043 M.

Explanation:

By plotting the relation between the natural log of concentration of $H_2O_2$ , the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.

Part a

Rate Law

The rate of the equation for 1st order reaction is given as

$Rate=k[H_2O_2]$

Part b

Integrated Rate Law

The integrated Rate Law is given as

$[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c

Value of the Rate Constant

Value of the rate constant is given by using the relation between 1st two observations i.e.

t1=0, M1=1.00

t2=120 s , M2=0.91

So k is calculated as

$-k(t_2-t_1)=ln{\frac{M_2}{M_1}}\\-k(120-0)=ln{\frac{0.91}{1.00}}\\k=\frac{-0.09431}{-120}\\k=7.8592 \times 10^{-4} s^{-1}$

The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d

Concentration after 4000 s is given as

$-k(t_2-t_1)=ln{\frac{M_2}{1.0}}\\-7.8592 \times 10^{-4}(4000-0)=ln{\frac{M_2}{1.00}}\\-3.1437=ln{\frac{M_2}{1.00}}\\M_2=e^{-3.1437}\\M_2=0.043 M$

Concentration after 4000 s is 0.043 M.

7 0

3 years ago

Did entropy increase or decrease?

seropon [69]

Answer:

1) increase

2) increase

Explanation:

Entropy is the degree of disorderliness or randomness of a system. It is the measure of the unavailable energy in a system.

Entropy increases with increase in the number of particles. If the number of particles in a system increases from left to right, the entropy of the system increases accordingly.

In reaction 1, the number of particles from left to right increased from two to three hence the entropy was increased.

In reaction 2, the number of particles from left to right increased from three to five hence the entropy was increased.

8 0

3 years ago

A class of substances known as __________ are used for their medicinal properties.

Misha Larkins [42]

Answer: Alkaloids

A class of substances known as alkaloids are used for their medicinal properties.

Explanation:

Alkaloids are small but complex organic substances with at least one nitrogen atom in its ring structure. Hence, they have strong basic properties, and are produced in naturally by some plants.

Examples of alkaloids and their medicinal properties are as follows:

- caffeine, used in certain drug and drinks to stimulate the nervous system

- morphine, used to reduce pain and induce sleep in humans.

- cocaine, nicotine etc

6 0

3 years ago

Read 2 more answers

A 50°C solution has a pH of 3.30. At this temperature, Kw = 5.48 x 10 9. What is the pOH of the solution?

sammy [17]

Answer:

9.93

Explanation: