Question

If a sample of gas of valume 605 mL and temperature of 39 OC, has 0,00803 moles. What is it’s pressure?

Answer 1

Answer:

The pressure of the gas is 0.35 atm.

Explanation:

We can find the pressure of the gas by using the Ideal Gas Law:

$P = \frac{nRT}{V}$

Where:

V: is the volume = 605 mL = 0.605 L

n: is the number of moles = 0.00803 moles

T: is the temperature = 39 °C = 312 K

R: is the gas constant = 0.082 L*atm/(K*mol)

Hence, the pressure is:

$P = \frac{0.0083 moles*0.082 L*atm/(K*mol)*312 K}{0.605 L} = 0.35 atm$

Therefore, the pressure of the gas is 0.35 atm.

I hope it helps you!