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azamat
3 years ago
7

Which is an example of kinetic energy?

Physics
2 answers:
alukav5142 [94]3 years ago
5 0
D . A hockey puck sliding across ice
lawyer [7]3 years ago
5 0

D. A hockey puck sliding across ice

You might be interested in
Calculate the magnitude of the focal length and power of a spherical mirror that has a radius of 5.00 cm.
yarga [219]

Answer:

2.5 cm

40 D

Explanation:

When the radius of curvature of a lens is divided by 2 we get the focal length of the lens.

Focal length is given by

f=\dfrac{R}{2}\\\Rightarrow f=\dfrac{5}{2}\\\Rightarrow f=2.5\ cm

The focal length of the lens is 2.5 cm

When we divide 1 by the focal length in the unit of meters we get the power of a lens

Power of a lens is given by

P=\dfrac{1}{f}\\\Rightarrow P=\dfrac{1}{0.025}\\\Rightarrow P=40\ D

The power of the lens is 40 D

5 0
4 years ago
Give an example of unbalanced force?​
Simora [160]

Answer:

If you kick a football and it moves from one place to another, it means that unbalanced forces are acting upon it. Ball moves from one place to another after kicking it. This is an example of unbalanced force.

Explanation:

5 0
3 years ago
What type of contraction requires the greatest amount of tension?
mars1129 [50]

Answer:

Isotonic eccentric

Explanation:

First of all, it should be noted that the term contraction has the meaning of joining or shortening. In the field of bodybuilding and workouts with loads, we can define muscle contraction as what happens whenever muscle fibers generate a tension in themselves.

This tension situation occurs in several situations, including when the muscle is shortened, elongated, moving, maintaining the same length or static.

There are different types of muscle contraction, among them we can highlight isotonic contraction, which is divided in turn into concentric and eccentric, isometric, auxotonic and isokinetic contraction.

 Isotonic contraction is the most common type of contraction that occurs in most sports or physical activities that we perform in our day to day. Normally the muscular tensions that we exert are usually accompanied by a shortening and lengthening of the muscle fibers of a muscle. In turn, the isotonic contraction is divided into two, concentric and eccentric.

Concentric concentration: is that which happens when a muscle makes a tension capable of overcoming a resistance, producing a shortening and subsequent mobilization of a part of the body overcoming said resistance. For example, when we take a spoon and take it to our mouths to eat, a concentric shortening occurs. Putting examples in the gym on the bench press the movement of raising the bar, is equivalent to the concentric phase.

Eccentric concentration: we can say that it is one in which, given a resistance, we exert a greater tension with the muscle, so that said muscle is lengthened. In the case of the bench press, the eccentric phase is when we lower the bar to the chest.

8 0
3 years ago
A rod of 2.0-m length and a square (2.0 mm × 2.0 mm) cross section is made of a material with a resistivity of 6.0 × 10–8 Ω ⋅ m.
Andrews [41]

Answer:

= 8.33 Watt

Explanation:

R = \frac{pl}{A}

where,

p = resistivity

l = length

A = cross section area

Given that ,

p = resistivity = 6.0 × 10–8 Ω

l = 2m

A = cross section area = 2.0 mm × 2.0 mm = 4 x 10^-6 m^2

A = 2 x 2 mm^2 = 4 x 10^-6 m^2

p = 6 x 10^-8 ohm metre,

V = 0.5 V

Let R be the resistance of the rod

R = p\frac{l}{A} \\\\R = 6.0 \times 10^-^8 (\frac{2}{4 \times 10^-^6} )\\\\R = 3 \times 10^-^2

R = 3 × 10⁻²Ω

Heat generated  = V^2 / R

= (0.5)^2 / (3 x 10^-2)

 = 8.33 Watt

5 0
3 years ago
If the rods with diameters and lengths listed below are made of the same material, which will undergo the largest percentage len
seraphim [82]

Answer:

The highest percentage of change corresponds to the thinnest rod, the correct answer is a

Explanation:

For this exercise we are asked to change the length of the bar by the action of a force applied along its length, in this case we focus on the expression of longitudinal elasticity

               F / A = Y ΔL/L

where F / A is the force per unit length, ΔL / L is the fraction of the change in length, and Y is Young's modulus.

In this case the bars are made of the same material by which Young's modulus is the same for all

              ΔL / L = (F / A) / Y

the area of ​​the bar is the area of ​​a circle

               A = π r² = π d² / 4

               A = π / 4 d²

we substitute

              ΔL / L = (F / Y) 4 /πd²

changing length

               ΔL = (F / Y 4 /π) L / d²

The amount between paracentesis are all constant in this exercise, let's look for the longitudinal change

a) values ​​given d and 3L

               ΔL = cte 3L / d²

               ΔL = cte L /d²  3

To find the percentage, we must divide the change in magnitude by its value and multiply by 100.

                ΔL/L % = [(F /Y  4/π 1/d²) 3L ] / 3L 100

                ΔL/L  % = cte 100%

 

b) 3d and L value, we repeat the same process as in part a

               ΔL = cte L / 9d²

               ΔL = cte L / d² 1/9

               ΔL / L% = cte 100/9

               ΔL / L% = cte 11%

   

c) 2d and 2L value

               ΔL = (cte L / d ½ )/ 2L

               ΔL/L% = cte 100/4

               ΔL/L% = cte 25%

d) value 4d and L

               ΔL = cte L / d² 1/16

                ΔL/L % = cte 100/16

                ΔL/L % = cte 6.25%

   

The highest percentage of change corresponds to the thinnest rod, the correct answer is a

5 0
3 years ago
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