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4 years ago

Calculate the magnitude of the focal length and power of a spherical mirror that has a radius of 5.00 cm.

Physics

1 answer:

yarga [219]4 years ago

5 0

Answer:

2.5 cm

40 D

Explanation:

When the radius of curvature of a lens is divided by 2 we get the focal length of the lens.

Focal length is given by

$f=\dfrac{R}{2}\\\Rightarrow f=\dfrac{5}{2}\\\Rightarrow f=2.5\ cm$

The focal length of the lens is 2.5 cm

When we divide 1 by the focal length in the unit of meters we get the power of a lens

Power of a lens is given by

$P=\dfrac{1}{f}\\\Rightarrow P=\dfrac{1}{0.025}\\\Rightarrow P=40\ D$

The power of the lens is 40 D

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Free fall condition : acceleration is constant downward and equals to gravitational acc.(g)

because velocity has opposite direction to acceleration, velocity will decrease as it rises.

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3 years ago

The graph is tied to the reading

AleksandrR [38]

I. Positive acceleration increases velocity. Negative acceleration decreases velocity. runner A sped up until the finish line and then slowed to a stop.

ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.

iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.

iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.

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3 years ago

An electric fan is running on HIGH. After the LOW button is pressed, the angular speed of the fan decreases to 84.7 rad/s in 2.9

ale4655 [162]

The initial angular speed of the fan will be 55.0 rad/sec. The angular speed of the fan decreases to 84.7 rad/s in 2.96 s.

<h3>What is angular acceleration?</h3>

Angular acceleration is defined as the pace of change of angular velocity with reference to time.

Given data;

Final angular speed, $\rm \omega_f = 84.7 rad/s$

Initial angular speed, $\rm \omega_i = ?$

Time period,t= 2.96 s

Angular deceleration = 47.2 rad/s²

$\rm \alpha =\frac{\omega_f-\omega_i}{t} \\\\\rm 47.2 =\frac{84.7-\omega_i}{2.96} \\\\ \omega_i = 55.0 \ rad/sec$

Hence the initial angular speed of the fan will be 55.0 rad/sec.

To know more about angular acceleration refer to the link ;

brainly.com/question/408236

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2 years ago

An astronaut and his space suit have a combined mass of 157 kg. The

alexgriva [62]

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

$-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})$

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

$-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]$

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3 years ago

Please solve the Problem.

babymother [125]

From the graph, the average acceleration between 5.0 s and 8.0 s is 2.33 ms^2.

<h3>What is acceleration?</h3>

The term acceleration has to do with the change in velocity with time. We can see that the graph shown is a graph of velocity against time, the slope of the graph is the acceleration.

Thus, the average acceleration between 5.0 s and 8.0 s can be read off from the graph as 20 m/s - 13m//8.0 s - 5.0 s = 2.33 ms^2.

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2 years ago