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pantera1 [17]
3 years ago
6

Calculate the percent by mass of C in pentaerythritol (C(CH2OH)4)

Chemistry
2 answers:
timofeeve [1]3 years ago
7 0
Formula for pentaerythritol = C5H12O4

mass of pentaerythritol = 5 (12) + 12 (1) + 4 (16)
= 60 + 12 + 64
= 138 amu

mass of C = 12 amu


% of C in C5H12O4 = [{5(12)}/ 138 ] × 100
= (60 / 138) × 100 = 43.47%
miskamm [114]3 years ago
7 0

Answer:

C= 44.12% % of C

Explanation:

Hi, the empirical formula of the pentaerythritol is {tex]C_5H_{12}O_4[/tex]

The molecular weights are:

M_C=12 g/mol

M_H=1 g/mol

M_O=16 g/mol

Due to the empirical formula in 1 mol of pentaerythritol you have 5 mol of C, 12 mol of H and 4 mol O

Taking a calculation base of 1 mol:

m_C=12 g/mol*5mol

m_C=60 g

m_H=1 g/mol*12mol

m_H=12 g

m_O=16 g/mol*4mol

m_O=64 g

The total weight will be:

m_{tot}=64 g +12 g +60 g= 136 gl

The C%:

C= \frac{m_C}{m_{tot}}*100%

C= \frac{60g}{136g}*100%

C= 44.12%

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