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Alexandra [31]
2 years ago
5

Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt

is added so that the solution conducts electricity, the tarnish disappears. Imagine that the two halves of this redox reaction were separated and connected with a wire and a salt bridge. Part A Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 V Cu2++2e−→Cu;E∘=0.340 V Express your answer to two decimal places and include the appropriate units.
Chemistry
1 answer:
oksian1 [2.3K]2 years ago
4 0

Answer:

The standard cell potential is 2.00 V

Explanation:

<u>Step 1:</u> Data given

Cu is cathode because of higher EP

Al3++3e−→Al       E∘=−1.66 V     anode

Cu2++2e−→Cu    E∘=0.340 V    cathode

<u>Step 2:</u> Balance both equations

2*(Al → Al3+-3e−)       E∘=1.66 V    

3*(Cu2++2e−→Cu)    E∘=0.340 V

<u>Step 3:</u> The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+  → 2Al3+ + 3Cu

<u>Step 4:</u> Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

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Answer:

66.7 g

Explanation:

Number of atoms = 2×10²¹

Mass of 2×10²¹ atoms = 0.4 g

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b) 1 mole of water is produced for every mole of carbon dioxide produced.

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b) Since in the chemical equation the stoichiometric coefficient of CO_{2}  and H_{2}O are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. <u>Therefore it is correct option.</u>

c)  6.02\times 10^{23} molecules is equal 1 mole of Na_{3}C_{6}H_{5}O_{7} if produced then 3 moles of NaHCO_{3} is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of H_{2}O (<em>Molecular Weight of water is 18 g</em>) is produced when 3 moles of NaHCO_{3} is used but in this option only one mole of NaHCO_{3} is given. So it is wrong.

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