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Sergeu [11.5K]
3 years ago
14

100 POINTS!!!!! YES,!!!!!!!! I SAID !!!!!!!100 POINTS!!!!!!!! FIRST TO ANSWER IT CORRECTLY AND ILL GIVE BRAINLY (LOOK IN THE TWO

PICS TO FIND AND THE CORRECT ANSWERS)!!!!!!!!

Physics
1 answer:
agasfer [191]3 years ago
3 0

"thanks for the points!!! and have a  (terrible) day"  - puppetasap4 :)

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Question:
klio [65]

The mass of the car should be A) 1212 kg

Explanation:

We can solve the problem by using Newton's second law of motion, which states that

F=ma

where:

F is the force produced by the engine

m is the mass of the car

a is its acceleration

In the first situation we have

m = 1515 kg

a=12 m/s^2 is the acceleration

Solving for F, we find the force produced by the engine:

F=(1515)(12)=18,180 N

Now we want the car to reach an acceleration of

a'=15 m/s^2

Using the same engine, therefore the force produced is still

F = 18,180 N

Re-arranging the equation for m', we find what should be the new mass of the car:

F=m'a'\\m' = \frac{F}{a'}=\frac{18180}{15}=1212 kg

Learn more about Newton's second law:

brainly.com/question/3820012

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6 0
3 years ago
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Do magnets work through glass?
Harrizon [31]
Yes but the thicker the glass the stronger the magnet has to be
7 0
3 years ago
Which illusion or test was most difficult for you to perceive correctly? Why do you think this particular illusion was so challe
Elan Coil [88]

Answer:

a condition in which is real or imagined in fear are difficult to control

7 0
3 years ago
A 96.0 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.240 m/s. How much work must be done on
Ede4ka [16]

Answer:

The work done by the hoop is equal to 5.529 Joules.

Explanation:

Given that,

Mass of the hoop, m = 96 kg

The speed of the center of mass, v = 0.24 m/s

To find,

The work done by the hoop.

Solution,

The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,

K_i=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

I is the moment of inertia, I=mr^2

Since, \omega=\dfrac{v}{r}

K_i=mv^2

K_i=96\times (0.24)^2=5.529\ J

Finally it stops, so the final energy of the hoop will be, K_f=0

The work done by the hoop is equal to the change in kinetic energy as :

W=K_f-K_i

W = -5.529 Joules

So, the work done by the hoop is equal to 5.529 Joules. Therefore, this is the required solution.

4 0
3 years ago
Which of the following is a way in which earth material is returned to the surface?
kvv77 [185]

Answer:

Explanation:

soil

4 0
3 years ago
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