Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is spun at 440.9 rad/s 440.9 rad/s while it is being read, and then is allowed to come to rest over 0.569 seconds 0.569 seconds , what is the magnitude of the average angular acceleration of the disk?

Answer 1

Answer:

-775 rad/s^2

Explanation:

Knowing the initial and final angular speed is $\omega_0 = 440.9 rad/s$ and $\omega = 0 rad/s$, respectively. We can use the following formula for equation of motion to calculate the average angular acceleration in t = 0.569 seconds

$\Delta \omega = \alpha t$

$\omega - \omega_0 = \alpha t$

$0 - 440.9 = \alpha 0.569$

$\alpha = \frac{-440.9}{0.569} = -775 rad/s^2$