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11Alexandr11 [23.1K]
3 years ago
11

A space-walking astronaut has become detached from her spaceship. She's floating in space with her handy tool belt attached to h

er waist, thinking about how she might get back to the ship, which she can see 50 meters from her current location.
How can she get back to the ship? Use language from the Laws of Motion in your answer.
Physics
1 answer:
ziro4ka [17]3 years ago
8 0

Astronauts on a spacewalk use the Newton's third law for navigation. Newton's third law states that every action has an equal and opposite reaction. Action and reaction forces act on different bodies.If  a person applies a force on an object, the object applies an equal and opposite force on the person.

The astronaut who has been detached from her spaceship, has a handy tool belt attached to her waist. If she throws a tool in a direction opposite to the direction of the location of the spaceship, the tool exerts an equal force on the astronaut, propelling her in the direction of the ship. To reach the ship, she can keep throwing tools, taking care to throw it  exactly in the opposite direction in which she needs to travel.

Every time a tool is thrown backwards, the astronaut will experience a force in the forward direction in accordance with Newton's third law, ultimately enabling her to get back to the ship.

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A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts
Tresset [83]

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

125 = 1250v

Divide both side by 1250

v = 125 / 1250

v = 0.1 m/s

Thus, the two cart will move with a velocity of 0.1 m/s after collision.

3 0
3 years ago
A solid must be given​
alexdok [17]
I- what....? Lolllll
8 0
3 years ago
A light bulb and a solenoid are connected in series to a battery. An irod rod is thrust rapidly into the solenoid and later rapi
Ivanshal [37]

Answer:

3) Dims in, Brightens out

Explanation:

The relationship between the inductance of a coil and the current is inverse.

As the rod is thrusted into the solenoid, the inductance increases, which in turn decreases the current and the bulb gets dimmer. This is also because some magnetic force is drawn away from the solenoid and the battery.

When the rod is removed, the inductance of the solenoid decreases, the current increases, and the bulb becomes brighter.

4 0
3 years ago
Read 2 more answers
Electrons in a particle beam each have a kinetic energy of 4.0 × 10 −17 J. What is the magnitude of the electric field that will
Dmitry_Shevchenko [17]

Answer:

-833.3 N/C

Explanation:

Kinetic energy, K, in terms of electric field, E, is given as:

K = qEr

q = charge = e = 1.6 × 10⁻¹⁹C

E = Electric field

r = distance = 0.3m

The electric field can be gotten by making E subject of formula:

E = K/(qr)

The electeic field needed to stop the electrons must be equal in magnitude to the electric field carried by these electrons:

E = (4.0 × 10⁻¹⁷)/(-1.6 × 10⁻¹⁹ * 0.3)

E = -833.3 N/C

This is the electric field needed to stop the electrons.

The negative sign means that the electric field must be in a direction opposite to the motion of the electrons.

3 0
3 years ago
Read 2 more answers
The average intensity of light emerging from a polarizing sheet is 0.708 W/m2, and that of the horizontally polarized light inci
Pachacha [2.7K]

Answer:

Angle θ = 30.82°

Explanation:

From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ

where;

I_o is the intensity of the polarized wave before passing through the filter.

In this question,

I is 0.708 W/m²

While I_o is 0.960 W/m²

Thus, plugging in these values into the equation, we have;

0.708 W/m² = 0.960 W/m² •cos²θ

Thus, cos²θ = 0.708 W/m²/0.960 W/m²

cos²θ = 0.7375

Cos θ = √0.7375

Cos θ = 0.8588

θ = Cos^(-1)0.8588

θ = 30.82°

4 0
4 years ago
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