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d1i1m1o1n [39]
3 years ago
8

If the equation of line M is 4x + 5y = 2 and the equation of line Nis

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0
Answer is True


Cause I know 100% Hope I could help my friend let me know if you need any other help:)
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FP!!!!!!!!!!!!!!!!!!! if ur up<br><br> ( 10 x 8 ) + 150
taurus [48]

Answer:

220

Step-by-step explanation:

<u>first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80</u>

<u>first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150</u>

<u>first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150 = 220</u>

<u> (10*8) +15</u>

<u>Solution</u>

<u>Solution= (80) +150</u>

<u>Solution= (80) +150= 80+150</u>

<u>Solution= (80) +150= 80+150=. 220</u>

<u>Solution= (80) +150= 80+150=. 220 </u>

8 0
3 years ago
Read 2 more answers
HELO ASAP ILL GIVE BRAINLIST
OverLord2011 [107]

Answer:

Option C is correct

Step-by-step explanation:

Plz help answer my question my lattes question plz

8 0
3 years ago
please answer asap! A couple plans to have 5 children. The gender of each child is equally likely. Design a simulation involving
dimulka [17.4K]

Step-by-step explanation:

The gender of a child which is either a boy or a girl is determined by the XX-chromosomes, or XY-chromosomes.

Since the couple plan to have 5 children, the chance of a child being a boy is equal to the chance of it being a girl - the chances are 50/50.

What we do to achieve our aim is to run a simulation that would add an X or Y to an X for all 5 children.

Doing this 125 times, we obtain the number of trials we desire.

For each trial, we get for each child, C:

C1: X + (X or Y)

C2: X + (X or Y)

C3: X + (X or Y)

C4: X + (X or Y)

C5: X + (X or Y)

Since the chance of having an X is equal to the chance of having a Y, they equal probability, which is 0.5 for each.

6 0
3 years ago
HG is the perpendicular bisector of FK.<br> What is the length of GH?<br> 8<br> 9<br> 15<br> 34
igor_vitrenko [27]

Answer:

GH=15

Step-by-step explanation:

HK= FK/2= 16/2= 8

Using pythagoras theorem in triangle GHK,

GH²= GK²-HK²

= 17²-8²

= 225

GH= √225

=15

4 0
3 years ago
Is the product of 2 perfect squares always a perfect square?
nexus9112 [7]
<span> The product of two perfect squares is a perfect square.

Proof of Existence:
Suppose a = 2^2 , b = 3^2 [ We have to show that the product of a and b is a perfect square.] then
c^2 = (a^2) (b^2)
= (2^2) (3^2)
= (4)9
= 36
and 36 is a perfect square of 6. This is to be shown and this completes the proof</span>
3 0
3 years ago
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