Answer:
Required number is 4.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of ten times the integer and seven times it’s square is 152.
= > Ten times of a + seven times of it's square = 152
= > 10( a ) + 7( a )^2 = 152
= > 10a + 7a^2 - 152 = 0
= > 7a^2 + 10a - 152 = 0
= > 7a^2 + ( 38 - 28 )a - 152 = 0
= > 7a^2 + 38a - 28a - 152 = 0
= > a( 7a + 38 ) - 4( 7a + 38 ) = 0
= > ( a - 4 )( 7a + 38 ) = 0
= > a = 4 or - 38 / 7
Hence the required number is 4.
-6(x + 8) > - 36
-6x - 48 > -36
-6x > -36 + 48
-6x > 12
x < -12/6
x < -2 <=== possible solutions are anything less then - 2......like -3,-4,-5 etc
About 224.7 I think. I hope this helps
Answer:
B
Step-by-step explanation:
both sides are equal to begin with so any x that you put in, will get multiplied by 7 and have 3 added to it
This value is very different from the other values
