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lions [1.4K]
3 years ago
9

if a bullet of unknown mass is fired from a gun with 50m/s. such that the recoil of the gun is -0.3m/s if the mass of gun is 8 k

g .find the mass of the bullet
Physics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

1333.34 kg

Explanation:

Given that,

The mass of the gun, m = 8 kg

Speed of the bullet, V = 50 m/s

The recoil speed of the gun, v = -0.3 m/s

We need to find the mass of the bullet. Using the conservation of momentum to find it. Let M is the mass of the bullet.

mv=MV\\\\M=\dfrac{mv}{V}\\\\=\dfrac{50\times 8}{0.3}\\\\=1333.34\ kg

So, the mass of the bullet is 1333.34 kg.

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You might have heard the phrase ‘hot air rises'. Name the process of transferring energy using moving gas or liquid.
Blizzard [7]

Answer: Convection

Explantion: Convection occurs when particles with a lot of heat energy in a liquid or gas move and take the place of particles with less heat energy. Heat energy is transferred from hot places to cooler places by convection

4 0
3 years ago
A 4,000 kg truck is moving at +10 m/s hits a 1500 kg parked car which moves off at +10 m/s. What is the velocity of the truck
Igoryamba

Answer:

10m/s

Explanation:

Using the law of conservation of momentums

M1u1+m2u2 = (m1+m2)v

Substitute.

4000(10)+1500(10) = (4000+1500)v

40,000+15,000 = 5,500v

55000 = 5500v

v = 55000/5500

v= 10m/s

Hence the velocity of the truck after Collision is 10m/s

6 0
3 years ago
Find the relation, time velocity graph : acceleration of an object, time position graph : ?
Anit [1.1K]

Answer:

In a time-position graph (s-t graph):

slope = velocity

In a time-velocity graph (v-t graph):

slope = acceleration

area under graph = change in displacement (distance travelled)

In a time-acceleration graph (a-t graph):

area under graph = change in velocity

8 0
3 years ago
A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy of 0.013 J.
Aleksandr [31]

answer

v = 4.2\frac{m}{s}

set up an equation

we can use the formula for kinetic energy since we know mass and kinetic energy

K = \frac{mv^{2}}{2}

v = \sqrt{\frac{2K}{m} }

values

K = 0.013 J

m = 1.5g = 0.0015 kg

plug in values

v = \sqrt{\frac{2*0.013}{0.0015} }

v = 4.2\frac{m}{s}

3 0
3 years ago
The magnitude of the velocity vector of the car is ∣∣v→∣∣ = 78 ft/s. If the vector v→ forms an angle θ = 0.09 rad with the horiz
kotegsom [21]

Answer:

\vec{v} = (77.68~{\rm ft/s})\^i + (7.01~{\rm ft/s})\^j

Explanation:

The x- and y- components of the velocity vector can be written as following:

\vec{v}_x = ||\vec{v}||\cos(\theta)\^i

\vec{v}_y = ||\vec{v}||\sin(\theta)\^j

Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows:

\vec{v} = 78\cos(0.09)\^i + 78\sin(0.09)\^j\\\vec{v} = (77.68~{\rm ft/s})\^i + (7.01~{\rm ft/s})\^j

3 0
3 years ago
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