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lions [1.4K]
3 years ago
9

if a bullet of unknown mass is fired from a gun with 50m/s. such that the recoil of the gun is -0.3m/s if the mass of gun is 8 k

g .find the mass of the bullet
Physics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

1333.34 kg

Explanation:

Given that,

The mass of the gun, m = 8 kg

Speed of the bullet, V = 50 m/s

The recoil speed of the gun, v = -0.3 m/s

We need to find the mass of the bullet. Using the conservation of momentum to find it. Let M is the mass of the bullet.

mv=MV\\\\M=\dfrac{mv}{V}\\\\=\dfrac{50\times 8}{0.3}\\\\=1333.34\ kg

So, the mass of the bullet is 1333.34 kg.

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A natural water molecule (H2O) in its vapor state has an electric dipole moment of magnitude, p = 6.2 x 10-30 C.m. (a) Find the
Vika [28.1K]

Answer:

a    D = 3.9 *10^{-12} \ m

b    \tau_{max} = 1.24 *10^{-25} \  N\cdot m

c   W =  2.48 *10^{-25} J

 

Explanation:

From the question we are told that

   The magnitude of electric dipole moment is  \sigma  =  6.2 *10^{-30} \ C \cdot m

     The electric field is E =  2*10^{4} \ N/C

   

The distance between the positive and negative charge center is mathematically evaluated as

     D =  \frac{\sigma }{10 e}

Where  e is the charge on one electron which has a constant value of  e = 1.60 *10^{-19} \ C

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     D =  \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}

      D = 3.9 *10^{-12} \ m

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       \tau_{max} = \sigma * E  * sin (\theta)

Here  \theta  =  90^o

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       \tau_{max} =  6.2 *10^{-30} * 2*10^{4} sin ( 90)

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The workdone is mathematically represented as

      W =  V_{(180)} - V_{0}

where   V_{(180)} is the potential energy at 180° which is mathematically evaluated as

     V_{(180) } = -   \sigma  * E  cos (180)

Where the negative signifies that it is acting against the  field

   substituting values

     V_{(180) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (180)

      V_{(180) } = 1.24*10^{-25} J

and

     V_{(0)} is the potential energy at 0° which is mathematically evaluated as

            V_{(0) } = -   \sigma  * E  cos (0)

   substituting values

     V_{(0) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (0)

      V_{(0) } =- 1.24*10^{-25} J

So W =  1.24 *10^{-25} - [-1.24 *10^{-25}]

    W =  2.48 *10^{-25} J

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