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ss7ja [257]
2 years ago
14

Write the equation for the acid dissociation, write the Ka expression, solve for Ht concentration, then do an ICE chart. Put the

values into the Ka expression (the one you solved for Ht and find Ht, convert to pH and input that to 2 decimal place. Or use the Henderson-Hasselbalch equation:
pH = pka, + log ( Base/Acid)
Calculate the pH of a buffer solution consisting of 0.39 M HA (Ka = 8.8 x 10^-6) and 0.2 M NaA.
Chemistry
1 answer:
serg [7]2 years ago
8 0

Answer:

The pH of the buffer is 4.77

Explanation:

Using Henderson-Hasselbalch equation we can solve the pH of the buffer:

pH = pKa + log [A⁻] / [HA]

<em>Where pH is the pH of the buffer</em>

<em>pKa is -log Ka = 5.056</em>

<em>[A⁻] = [NaA] = 0.2M</em>

<em>[HA] = 0.39M</em>

<em />

Replacing:

pH = 5.056+ log [0.2] / [0.39]

pH = 4.77

<h3>The pH of the buffer is 4.77</h3>

<em />

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