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ss7ja [257]
3 years ago
14

Write the equation for the acid dissociation, write the Ka expression, solve for Ht concentration, then do an ICE chart. Put the

values into the Ka expression (the one you solved for Ht and find Ht, convert to pH and input that to 2 decimal place. Or use the Henderson-Hasselbalch equation:
pH = pka, + log ( Base/Acid)
Calculate the pH of a buffer solution consisting of 0.39 M HA (Ka = 8.8 x 10^-6) and 0.2 M NaA.
Chemistry
1 answer:
serg [7]3 years ago
8 0

Answer:

The pH of the buffer is 4.77

Explanation:

Using Henderson-Hasselbalch equation we can solve the pH of the buffer:

pH = pKa + log [A⁻] / [HA]

<em>Where pH is the pH of the buffer</em>

<em>pKa is -log Ka = 5.056</em>

<em>[A⁻] = [NaA] = 0.2M</em>

<em>[HA] = 0.39M</em>

<em />

Replacing:

pH = 5.056+ log [0.2] / [0.39]

pH = 4.77

<h3>The pH of the buffer is 4.77</h3>

<em />

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Answer:

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Do metals form anions or cations
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6 0
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Identify the blocks and groups of elements in the periodic table​
djyliett [7]

Explanation:

The periodic table is a table that arranges elements based on their atomic numbers into groups and periods.

The groups are the vertical arrangement of elements. All elements in a group share similar chemical properties because they have the same number of elements in their valence shell. The periodic table groups are:

               Group                             Other names

              1A or 1                               Alkali metals

              IIA or 2                              Alkaline earth metals

             IIIA or 3                            Boron family

             VIA or 6                             Chalcogens

            VIIA or 17                            Halogens

             O-18                                  Inert elements

             IIIB-IIB                              Transition elements

There are 18 vertical columns divided into 8 tall groups or main groups which are 1A to O. The short groups or subgroups are from numerals 1B to VIII.

The periodic table can be divided into four blocks based on the type of sublevels their valence electrons occupy.

  • Group IA and IIA constitute the s-block
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3 0
3 years ago
(c) Assume you have an equilibrium mixture of [A], [B], and [C] at 298K and that the
djyliett [7]

Answer:

Explanation:

1. The amount of CaCO3 must be so small that  

P

CO

2

 is less than KP when the CaCO3 has completely decomposed. In other words, the starting amount of CaCO3 cannot completely generate the full  

P

CO

2

 required for equilibrium.

3. The change in enthalpy may be used. If the reaction is exothermic, the heat produced can be thought of as a product. If the reaction is endothermic the heat added can be thought of as a reactant. Additional heat would shift an exothermic reaction back to the reactants but would shift an endothermic reaction to the products. Cooling an exothermic reaction causes the reaction to shift toward the product side; cooling an endothermic reaction would cause it to shift to the reactants’ side.

5. No, it is not at equilibrium. Because the system is not confined, products continuously escape from the region of the flame; reactants are also added continuously from the burner and surrounding atmosphere.

7. Add N2; add H2; decrease the container volume; heat the mixture.

9. (a) ΔT increase = shift right, ΔP increase = shift left; (b) ΔT increase = shift right, ΔP increase = no effect; (c) ΔT increase = shift left, ΔP increase = shift left; (d) ΔT increase = shift left, ΔP increase = shift right.

11. (a)  

K

c

=

[

CH

3

OH

]

[

H

2

]

2

[

CO

]

; (b) [H2] increases, [CO] decreases, [CH3OH] increases; (c), [H2] increases, [CO] decreases, [CH3OH] decreases; (d), [H2] increases, [CO] increases, [CH3OH] increases; (e), [H2] increases, [CO] increases, [CH3OH] decreases; (f), no changes.

13. (a)  

K

c

=

[

CO

]

[

H

2

]

[

H

2

O

]

; (b) [H2O] no change, [CO] no change, [H2] no change; (c) [H2O] decreases, [CO] decreases, [H2] decreases; (d) [H2O] increases, [CO] increases, [H2] decreases; (f) [H2O] decreases, [CO] increases, [H2] increases. In (b), (c), (d), and (e), the mass of carbon will change, but its concentration (activity) will not change.

15. Only (b)

17. Add NaCl or some other salt that produces Cl− to the solution. Cooling the solution forces the equilibrium to the right, precipitating more AgCl(s).

19. (a)

Hope this helps :)

3 0
3 years ago
He reaction produces 1.6 g of gas in 30 seconds.Calculate the mean rate of the reaction in the first 30 seconds.Use the equation
devlian [24]

Answer:

Mean rate of reaction produced = 0.533 g/sec (approx.)

Explanation:

Given:

Reaction produced = 1.6 gram

Time taken = 30 sec

Find:

Mean rate of reaction produced

Computation:

Mean rate of reaction produced = Reaction produced / Time taken

Mean rate of reaction produced = 1.6 / 30

Mean rate of reaction produced = 0.533 g/sec (approx.)

5 0
3 years ago
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