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ss7ja [257]
2 years ago
14

Write the equation for the acid dissociation, write the Ka expression, solve for Ht concentration, then do an ICE chart. Put the

values into the Ka expression (the one you solved for Ht and find Ht, convert to pH and input that to 2 decimal place. Or use the Henderson-Hasselbalch equation:
pH = pka, + log ( Base/Acid)
Calculate the pH of a buffer solution consisting of 0.39 M HA (Ka = 8.8 x 10^-6) and 0.2 M NaA.
Chemistry
1 answer:
serg [7]2 years ago
8 0

Answer:

The pH of the buffer is 4.77

Explanation:

Using Henderson-Hasselbalch equation we can solve the pH of the buffer:

pH = pKa + log [A⁻] / [HA]

<em>Where pH is the pH of the buffer</em>

<em>pKa is -log Ka = 5.056</em>

<em>[A⁻] = [NaA] = 0.2M</em>

<em>[HA] = 0.39M</em>

<em />

Replacing:

pH = 5.056+ log [0.2] / [0.39]

pH = 4.77

<h3>The pH of the buffer is 4.77</h3>

<em />

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Answer:

burning of wood ,cooking an egg,baking a cake,rusting of iron,digestion of food .

8 0
2 years ago
Water readily sticks to many other substances, a property called ______. Water readily sticks to many other substances, a proper
Ahat [919]

Answer:

Option (2)

Explanation:

Cohesion is usually defined as the contrasting property by which the water molecules are attached to one another, and adhesion is the property by which the molecular substances are linked to the molecules of other substances.

Since, the water molecules are able to form inter-molecular hydrogen bonding, so they are comprised of strong cohesive force.

And, as the water molecules are able to stick to the walls of the container, so they tend to show more of the properties for adhesion.

Thus, according to the given condition, water molecules are sticking to other substances and this is the property of adhesion.

Hence, the correct answer is option (2).

4 0
2 years ago
Write the balanced chemical equation where liquid decane burns in oxygen gas to form carbon dioxide gas and water vapor. Use the
Allushta [10]

Answer:

2C_{10} H_{22(l)} + 31O2(g)--> 20CO_{2(g)} + 22H_{2}O_{(g)}

Explanation:

2C_{10} H_{22(g)} + 31O2(g)--> 20CO_{2(g)} + 22H_{2}O_{(g)}

From the question, one can work out which states of matter to assign to which species. The trick with organic equations of this nature is to try to balance everything but oxygen first. Make sure you balance oxygen last because it is the easiest to balance.

3 0
3 years ago
Suppose you have 75 gas-phase molecules of methanol (CH3OH) at T = 470 K. These molecules are contained in a spherical container
Katarina [22]

Answer:

The average pressure in the container due to these 75 gas molecules is P=9.72 \times 10^{-16} Pa

Explanation:

Here Pressure in a container is given as

P=\frac{1}{3} \rho

Here

  • P is the pressure which is to be calculated
  • ρ is the density of the gas which is to be calculated as below

                                         \rho =\frac{mass}{Volume of container}

        Here

                mass is to be calculated for 75 gas phase molecules as

                      m=n_{molecules} \times \frac{1 mol}{6.022 \times 10^{23} molecules} \times \frac{32 g/mol}{1 mol}\\m=75 \times \frac{1 mol}{6.022 \times 10^{23} molecules} \times \frac{32 g/mol}{1 mol}\\m=3.98 \times  10^{-21} g

              Volume of container is 0.5 lts

     So density is given as

                         \rho =\frac{mass}{Volume of container}\\\rho =\frac{3.98 \times 10^{-21} \times 10^{-3} kg}{0.5 \times 10^{-3} m^3}\\\rho =7.97 \times 10^{-21}\, kg/m^3

  • is the mean squared velocity which is given as

                                        =RMS^2

      Here RMS is the Root Mean Square speed given as 605 m/s so

                                      =RMS^2\\=(605)^2\\=366025

Substituting the values in the equation and solving

P=\frac{1}{3} \rho \\P=\frac{1}{3} \times 7.97 \times 10^{-21} \times 366025\\P=9.72 \times 10^{-16} Pa

So the average pressure in the container due to these 75 gas molecules is P=9.72 \times 10^{-16} Pa

6 0
3 years ago
How many moles of iron can be produced from 4.20 moles of iron (III) oxide?
Kay [80]
Hope this helps, have a nice day ahead!

6 0
3 years ago
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