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ss7ja [257]
2 years ago
14

Write the equation for the acid dissociation, write the Ka expression, solve for Ht concentration, then do an ICE chart. Put the

values into the Ka expression (the one you solved for Ht and find Ht, convert to pH and input that to 2 decimal place. Or use the Henderson-Hasselbalch equation:
pH = pka, + log ( Base/Acid)
Calculate the pH of a buffer solution consisting of 0.39 M HA (Ka = 8.8 x 10^-6) and 0.2 M NaA.
Chemistry
1 answer:
serg [7]2 years ago
8 0

Answer:

The pH of the buffer is 4.77

Explanation:

Using Henderson-Hasselbalch equation we can solve the pH of the buffer:

pH = pKa + log [A⁻] / [HA]

<em>Where pH is the pH of the buffer</em>

<em>pKa is -log Ka = 5.056</em>

<em>[A⁻] = [NaA] = 0.2M</em>

<em>[HA] = 0.39M</em>

<em />

Replacing:

pH = 5.056+ log [0.2] / [0.39]

pH = 4.77

<h3>The pH of the buffer is 4.77</h3>

<em />

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Answer:

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How much 3.0 M NaOH is needed to neutralize 30. mL of 0.75 M H2SO4?
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Answer:

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Explanation:

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3 years ago
Methane (CH4), is said to be the cleanest burning fossil fuel. When burned, it releases carbon dioxide gas and forms water. Usin
LiRa [457]

From the stoichiometry of the balanced reaction equation, the correct statement are;

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  • For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.

<h3>What is combustion?</h3>

The term combustion refers to the burning of fossil fuels for the purpose of energy production. The equation for reaction is CH4 + 2O2 ---> CO2 + 2H2O.

Using this equation as shown, the true statements are;

  • For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
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3 0
2 years ago
Provide an explanation that is grounded in polarity that better explains why oil is not miscible in vinegar.
butalik [34]

Explanation:

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4 0
2 years ago
Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
Alborosie

<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

Ans: Ka for HNO3 = 1.23

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3 years ago
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