Answer: 27.09 ppm and 0.003 %.
First, <u>for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. </u>Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.
Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.
So, according to the <em>law of ideal gases,</em>
PV = nRT
where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the constant gas (0.082057 atm L / mol K)
The moles of CO will be,
n = 35 mg x
x
→ n = 0.00125 mol
We clear V from the equation and substitute P = 0.92 atm and
T = -30 ° C + 273.15 K = 243.15 K
V = 
→ V = 0.0271 L
As 1000 cm³ = 1 L then,
V = 0.0271 L x
= 27.09 cm³
<u>Then the acceptable concentration </u><u>c</u><u> of CO in ppm is,</u>
c = 27 cm³ / m³ = 27 ppm
<u>To express this concentration in percent by volume </u>we must consider that 1 000 000 cm³ = 1 m³ to convert 27.09 cm³ in m³ and multiply the result by 100%:
c = 27.09
x
x 100%
c = 0.003 %
So, <u>the acceptable concentration of CO if the temperature is -30 °C and pressure is 0.92 atm in ppm and as a percent by volume is </u>27.09 ppm and 0.003 %.
Answer:
I think it is C
Explanation:
Hope this helps!! :)
If I'm wrong, then greatest apologies
Hello.
<span>It makes a longitudinal wave because it stretches and compresses while as it slithers foward.
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Have a nice day
Converting mmHg to atm is solved by division.
Example: Convert 745.0 to atm.
Solution- divide the mmHg value by the 760.0 mmHg / atm.
745 mmHg over 760.0 mmHg/atm
atm value is 0.980263
Now, I am a medical student and we have never had to convert a BP (blood pressure) to atm from mmHg, only ever kPA. SO, I am going to take a guess here and say that when you do the work to solve this, you are going to convert the Systolic (upper #) which is the 145. You should get 0.190789 and then convert the Diastolic (lower #) which is 65. You should get 0.08552632.
So your fraction so to speak should read, 0.190789/0.08552632 or 0.190789 over 0.08552632
(Just to note that is way to low of a BP, although it is irrelevant) Best wishes and good luck. "Remember, never just look for the right answer, look for why it is the right answer!"
Answer:
- Third choice:<em> energy present in the glucose and oxygen that is not needed for the formation of carbon dioxide and water is released to form energy/ATP.</em>
Explanation:
<u>1) Chemical equation (given):</u>
- C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy
<u>2) Chemical potential energy:</u>
Each compound stores chemical potential energy. This energy is stored in the chemical bonds.
Due to every substance has its own unique chemical potential energy, when a chemical reaction takes plase, yielding to the change of some substances, some energy is absorbed (when bonds are formed) and some energy is released (when bonds are broken).
<u>3) Conservation of energy:</u>
Then, if the sum of the bond energies of the final products is less than the sum of the bond energies of the reactants, the<em> law of conservation of energy</em> rules that the difference between the total energies of the products and reactants must be released to the surroundings.
That is what is happening in the given reaction:
- C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy
The term energy in the product side means that energy is conserved because it is being released due to the the glucose and oxygen (reactant side) have more energy stored in their bonds than the energy needed for the formation of carbon dioxide and water, so that excess of energy is released to form energy/ATP.
<u>Summarizing:</u>
- The energy on the product side added to the energy of carbon dioxide and water equals the energy of the glucose and oxygen and the final balance is:
- ∑ Energy of the reactants = ∑energy of the products + released energy, supporting the law of conservation of energy.