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Brums [2.3K]
3 years ago
15

I am running a reaction that creates 138 grams of sulfur trioxide (S03). My theoretical yield was 156 grams. What is my percenta

ge yield?​
Chemistry
1 answer:
alex41 [277]3 years ago
5 0

Answer:

88.46%

Explanation:

Percentage yield is actual/theoretical * 100

138/156 * 100 = 88.4615385

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If the Earth had no tilt, how would that affect our seasons? I will give branliest to first comment
Aleks [24]

Answer:

in my opinion it wouldn't be regular seasons like what we have now it would be equal in every poles .. there would not be ice in North. [its my opinion though] sorry if I am wrong

6 0
3 years ago
Which mixture can be classified as a homogeneous mixture?
Reika [66]
Anything can be homogenous as long as you can only see the same type of liquid
think about it like this
orange juice with pulp is Hetero
orange juice with no pulp is homo
3 0
3 years ago
Read 2 more answers
Can someone provide a answer with explanation for this question? Thanks!
zhuklara [117]

Answer:

Explanation:

B

4 0
1 year ago
A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode c
Andre45 [30]

<u>Answer:</u> The standard potential of the cell is 0.77 V

<u>Explanation:</u>

We know that:

E^o_{Ni^{2+}/Ni}=-0.25V\\E^o_{Cu^{+}/Cu}=0.52V

The substance having highest positive E^o reduction potential will always get reduced and will undergo reduction reaction.

The half reaction follows:

<u>Oxidation half reaction:</u> Ni(s)\rightarrow Ni^{2+}(aq)+2e^-

<u>Reduction half reaction:</u> Cu^{+}(aq)+e^-\rightarrow Cu(s)       ( × 2)

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation follows:

E^o_{cell}=0.52-(-0.25)=0.77V

Hence, the standard potential of the cell is 0.77 V

5 0
3 years ago
How many sucrose molecules are in 3.0 moles of sucrose scientific
DiKsa [7]
Answer:
             1.80 × 10²⁴ Molecules of Sucrose

Solution:

Number of Moles and Number of Particles (molecules in given case) are related to each other as,

                  Moles  =  Number of Molecules ÷ 6.022 × 10²³

Solving for Number of Molecules,

                  Number of Molecules  =  Moles × 6.022 × 10²³

Data Given;
                     Moles  =  3 moles

Putting values in eq,


                 Number of Molecules  =  3 mol × 6.022 × 10²³


                 Number of Molecules  =  1.80 × 10²⁴ Molecules
3 0
3 years ago
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