486 kPa will be the pressure of gas at 27 degrees.
Explanation:
Data given :
Initial pressure of the gas P1 = 810 kPa
initial temperature of the gas T1 = 227 degrees OR 500.15 K
final pressure of the gas =?
final temperature of the gas = 27 degrees OR 300.15 K
Gay Lussac's law is used to calculate the pressure of the gas at 27 degrees or 300.15 K
= 
P2 = 
Putting the values in the equation:
P2 = 
P2 = 486 KPa
486 Kpa is the pressure of the gas when temperature was reduced to 27 degrees.
The given data is as follows:
Element 1st IE
1 1310 kJ/mol
2 1011 kJ/mol
3 418 kJ/mol
4 2080 kJ/mol
5 947 kJ/mol
Ionization energy is the amount of energy required to remove an electron from an atom. It reflects the tendency of an atom to give away electrons readily. Lower the IE, more easily will the electron be lost. Low values of IE are characteristic of metals whereas, non-metals have higher IE values.
Based on the given data:
Element 4 is likely to be a non-metal
Element 3 is likely to be a metal