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3 years ago

A gas has a pressure of 810 kPa at 227°C. What will its pressure be at 27°C?

Chemistry

1 answer:

NeX [460]3 years ago

5 0

486 kPa will be the pressure of gas at 27 degrees.

Explanation:

Data given :

Initial pressure of the gas P1 = 810 kPa

initial temperature of the gas T1 = 227 degrees OR 500.15 K

final pressure of the gas =?

final temperature of the gas = 27 degrees OR 300.15 K

Gay Lussac's law is used to calculate the pressure of the gas at 27 degrees or 300.15 K

$\frac{P1}{T1}$ = $\frac{P2}{T2}$

P2 = $\frac{P1T2}{T1}$

Putting the values in the equation:

P2 = $\frac{810 X 300.15}{500.15}$

P2 = 486 KPa

486 Kpa is the pressure of the gas when temperature was reduced to 27 degrees.

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3 years ago

Iodine monochloride (ICl) has a higher boiling point than bromine (Br2) partly because iodine monochloride is a(n)

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Explanation:

The boiling point is the temperature at which the vapor pressure of a liquid equals the external pressure surrounding the liquid. The boiling point is dependent on the type of forces present.

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2 years ago

Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con

erik [133]

Explanation:

The given data is as follows.

Thickness (dx) = 0.87 m, thermal conductivity (k) = 13 W/m-K

Surface area (A) = 5 $m^{2}$ , $T_{1} = 14^{o}C$

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According to Fourier's law,

Q = $-kA \frac{dT}{dx}$

Hence, putting the given values into the above formula as follows.

Q = $-kA \frac{dT}{dx}$

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3 years ago

What is the longest wavelength in the Balmer series? (Hint: the Rydberg constant for Hydrogen is 1.096776×107 1/m, and the Balme

boyakko [2]

Answer: The longest wavelength of light is 656.5 nm

Explanation:

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