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Sloan [31]
2 years ago
12

Please please i need help i did not understand it

Mathematics
2 answers:
Ymorist [56]2 years ago
5 0

Answer:

<h2><em><u>h</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>20</u></em><em><u> </u></em><em><u>ft</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

Volume = 5600 sq.ft

Length = 35 ft

Width = 8 ft

<em><u>Therefore</u></em><em><u>, </u></em>

<em>By</em><em> </em><em>the</em><em> </em><em>problem</em><em>, </em>

height =  \frac{volume}{length \times width}

=  > h =  \frac{5600}{35 \times 8} ft

=> <em><u>h = 20 </u></em><em><u>ft</u></em><em><u> </u></em><em><u>(Ans)</u></em>

Keith_Richards [23]2 years ago
4 0
V=l*w*h
5600=35*8h
Multiply 35 times 8, which you’ll get 280
5600=280h
Divide both sides
5600/280=280h/280
20=h
Therefore h=20ft is your answer <3
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A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

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3 years ago
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