Answer:
See explanation
Explanation:
If i have a sodium halide salt which can be any of NaCl, NaBr, or NaI, addition of AgNO3 and ammonia leads to the formation of various colour of precipitate which helps to identify the particular halogen atom that is combined with sodium.
If the sodium halide is NaCl, a white precipitate is formed when AgNO3 is added. The precipitate is soluble in ammonia solution.
If the sodium halide is NaBr, a cream precipitate is formed when AgNO3 is added. This precipitate is sparingly soluble in excess ammonia solution.
If the sodium halide is NaI, a yellow precipitate is formed when AgNO3 is added. This precipitate is insoluble in excess ammonia solution
b) The true color of a halogen is only observed when it is viewed in hexane. iodine in hexane has a purple colour. Hence, the reaction that occured is;
NaI(aq) + Cl2 → NaCl(aq) + I2
Answer:reaction 2,5,6
Explanation:
First, we need to define what the enthalpy of formation is and what the enthalpy of reaction is____
<u>Formation Enthalpy</u>: It is the variation of the calorific energy in the reaction of ONE MOL of a compound starting from the elements.
<u>Reaction Enthalpy: </u>It s the variation of the calorific energy in the reaction of reactives, in this cases could be any quantity of mol
Then: We have six reactions:
1)CaCO3(g)→ CaO+ CO2(g)
2)Li(s)+12F2(g)→LiF(s)
3)CO(g)+12 O2(g)→ CO2(g)
4)2Li(s)+F2(g)→2LiF(s)
5)Li(s)+12F2(l)→LiF(s)
6)C(s,graphite)+ O2(g)→ CO2(g)
The enthalpy of reaction will be equal to reaction enthalpy when we produce one mol from elements
The answer is the reactions 2,5,6
1. homogenous: sugar solution
2. heterogeneous: sand solution
3. compound: water
4. physical change: ice melting
5. element: hydrogen
6. chemical change: burning fire