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2 years ago

12

Indicate the type of wave motion of a flag waving in a breeze

2 answers:

Mazyrski [523]2 years ago

8 0

Answer:

Transverse waves, because the motion of the wave is perpendicular to the direction of propagation. An S-wave is an example of a transverse wave.

Explanation:

mart [117]2 years ago

5 0

Transverse wave and it’s example is an s-shaped and that’s the motion of a flag waving in a breeze

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According to meet one law of universal gravitation, gravity increases when?

mina [271]

Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between them. Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between them.

5 0

2 years ago

Newton's Law of Cooling says that the rate of cooling of an object is proportional to the difference between its own temperature

ASHA 777 [7]

Answer:

$\frac{dQ}{dt} =-hA\Delta T(t)$

Explanation:Newton.s law of cooling states that the rate of cooling of an object is proportional to the difference between its own temperatures and temperature of its surroundings. Mathematically,

$\frac{dQ}{dt} =-hA [T(t)-T(s)]\\$

$\frac{dQ}{dt} =-hA\Delta T(t)$

where $Q$ is the heat transfer

$h$ is heat transfer coefficient

$A$ is the heat transfer surface area

$T$ is the temperature of the object's surface

$T(s)$ is the temperature of the surroundings

3 0

2 years ago

The average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km. How much

aleksklad [387]

Answer:

Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

Explanation:

We have been given that the average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km.

We will use Kepler's Law to solve our given problem.

$\frac{(T_1)^2}{(T_2)^2}=\frac{(r_1)^3}{(r_2)^3}$

Upon substituting our given values, we will get:

$\frac{(T_1)^2}{(T_2)^2}=\frac{(238,000)^3}{(1,222,000)^3}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272000000000}{1824793048000000000}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272}{1824793048}$

$\frac{(T_1)^2}{(T_2)^2}=0.0073878361246365$

Taking square root of both sides, we will get:

$\frac{T_1}{T_2}=\sqrt{0.0073878361246365}$

$\frac{T_1}{T_2}=0.0859525225030452495$

$\frac{T_2}{T_1}=\frac{1}{0.0859525225030452495}$

$\frac{T_2}{T_1}=11.634329870476699\approx 11.634$

$T_2=11.634\cdot T_1$

This implies that time period of Titan about Sturn is 11.634 times more compared to time period of Enceladus about Saturn.

So, basically Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

8 0

2 years ago

???????????!??!!!!!!!!

Diano4ka-milaya [45]

The answer would be B.

6 0

2 years ago

if a boat was moving at a velocity of 30 m/s to the south and it sailed for 30 minutes, what was the displacement of the boat?

kifflom [539]

If you move south at 30 m/s for 30 minutes, your displacement is

D = (30 mtr/s) x (30 min) x (60 sec/min)

D = (30 x 30 x 60) (mtr-min-sec/sec-min)

D = 54,000 meters south

D = <em>54 km south</em>

8 0

2 years ago