Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
Hey can someone help me with my latest question no one‘s helping me and I really need it
Answer:
A. 1
Step-by-step explanation:
I see only one red function line in the graph. this line represents the simple function y = 1, for x in the interval [-2,1].
the domain of a function defines the possible values for x, and the range of a function defined the possible values for y.
this function has only one possible value for y : 1
so, only A applies.
