Answer:
W = 9533.09 Watt
Explanation:
given,
diameter of pipe inlet, d₁ = 10 cm
r₁ = 5 cm
diameter of pipe outlet, d₂ = 15 cm
r₂= 7.5 cm
head upto water level is to rise = 60 + 5
= 65 m
flow rate = 0.015 m³/s
we know
A₁ v₁ = A₂ v₂ = Q
π r₁² v₁ = π r₂² v₂ = 0.015
v₂ = 0.848 m/s
v₁ = 1.908 m/s
Applying Bernoulli's equation
P_p is the pump pressure
Power of the pump
W = P_p x Q
W = 635539.32 x 0.015
W = 9533.09 Watt
Answer:
<h2>line B</h2>
Explanation:
According to ohm's law V = IR where;
V i sthe supply voltage (in volts)
I = supply current (in amperes)
R = resistance (in ohms)
In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.
For line B, R = ΔV/ΔI
R = V₂-V₁/I₂-I₁
R = 14.0-4.0/7.0-2.0
R = 10.0/5.0
R = 2.0ohms
Since the slope of line B is equal to 2 ohms, this shows that the line B is the one that represents the 2ohms resistor.
Answer:
if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.
Explanation:
The air in the tube can be considered an ideal gas,
P V = nR T
In that case we have the tube in the air where the pressure is P1 = P_atm, then we introduce the tube to the water to a depth H
For pressure the open end of the tube is
P₂ = P_atm + ρ g H
Let's write the gas equation for the colon
P₁ V₁ = P₂ V₂
P_atm V₁ = (P_atm + ρ g H) V₂
V₂ = V₁ P_atm / (P_atm + ρ g h)
If the air obeys Boyle's law e; volume within the had must decrease due to the increase in pressure, if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.
The main assumption is that the temperature during the experiment does not change
The answer should be 1.6 kilometers.
Answer:
Explanation:
W = 75 watts
V = 110 volts
Formula
W = V * I
Solution
75 = 110 * I Divide by 110
75 / 110 = I
I = 0.6818 Amperes
