Answer:
The temperature of the core raises by every second.
Explanation:
Since the average specific heat of the reactor core is 0.3349 kJ/kgC
It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius
Thus reactor core whose mass is will require
energy to raise it's temperature by 1 degree Celsius in 1 second
Hence by the concept of proportionately we can infer 150 MW of power will increase the temperature by
To solve the problem it is necessary to take into account the concepts related to energy efficiency in the engines, the work done, the heat input in the systems, the exchange and loss of heat in the soupy the radius between the work done the lost heat ( efficiency).
By definition the efficiency of the heat engine is
Where,
Temperature at the room
Temperature of the soup
The work done is defined as,
Where represents the input heat and at the same time is defined as
Where,
Specific Heat
The change at the work would be defined then as
On the other hand we have that the heat lost by the soup is equal to
The ratio between both would be,
Replacing with our values we have,
Therefore the fraction of heat lost by the soup that can be turned into useable work by the engine is 0.0613.
Answer:
Explanation:
The stunt will likely sustain serious injury in case of concrete blocks because the average force acting on the person will be more because concrete blocks do not squeeze to provide more time for the force to act on the body instead it acts for a small amount of interval.
As impulse is constant so time requires to act force on the body is more as compared to concrete block and thus average force in mattress case is less.