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Aneli [31]
3 years ago
9

How is an electromagnet different from a magnet?

Physics
1 answer:
RSB [31]3 years ago
5 0

Answer: b . An electromagnet can be changed by changing the amount of current.

Explanation:

In an <u>electromagnet</u>, <u>the magnetic field is generated by an electric current in a coil of wire which reinforces an iron core. But when the electric current applied on the mentioned core is disconnected, it immediately loses its magnetization</u>. This also means that the intensity of the magnetic field can be controlled (increased or decreased) by changing the intensity of the electric current flowing through the nucleus.

On the other hand, the <u>permanent magnet</u> <u>does not depend on electric current to magnetize</u>, because <u>due to its composition (a ferromagnetic material)</u> the magnetization capacity continues even after not being in contact with an external magnetic field.

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Verizon [17]

Answer:

A & D

Explanation:

:p

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3 years ago
A centripetal force causes circular motion because it accelerates an object
MAVERICK [17]

The answer is option A.

Centripetal force is always directed towards the centre and does not change the speed of the body,but there is a change in the direction.

6 0
3 years ago
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An investigator collects a sample of a radioactive isotope with an activity of 490,000 Bq.48 hours later, the activity is 110,00
Daniel [21]

Answer:

The correct answer is "22.27 hours".

Explanation:

Given that:

Radioactive isotope activity,

= 490,000 Bq

Activity,

= 110,000 Bq

Time,

= 48 hours

As we know,

⇒ A = A_0 e^{- \lambda t}

or,

⇒ \frac{A}{A_0}=e^{-\lambda t}

By taking "ln", we get

⇒ ln \frac{A}{A_0}=- \lambda t

By substituting the values, we get

⇒ -ln \frac{110000}{490000} = -48 \lambda

⇒    -1.4939=-48 \lambda

                 \lambda = 0.031122

As,

⇒ \lambda = \frac{ln_2}{\frac{T}{2} }

then,

⇒ \frac{ln_2}{T_ \frac{1}{2} } =0.031122

⇒ T_\frac{1}{2}=\frac{ln_2}{0.031122}

         =22.27 \ hours  

3 0
3 years ago
Ft-Fg= ma solve for a
densk [106]
The answer is a= Ft-Fg/m
8 0
3 years ago
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The maximum allowable resistance for an underwater cable is one hundredth of an ohm per
Studentka2010 [4]

Answer:

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

Explanation:

The resistance of a wire can be given by the following formula:

R = \frac{\rho L}{A}\\\\A = \frac{\rho L}{R} = \frac{\rho}{\frac{R}{L} }

where,

A = smallest cross-sectional area = ?

ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm

\frac{R}{L} = resistance per unit length of wire = 0.001 Ω/m

Therefore,

A = \frac{1.54\ x\ 10^{-8}\ \Omega m}{0.001\ \Omega/m}

<u>A = 1.54 x 10⁻⁵ m² = 15.4 mm²</u>

6 0
3 years ago
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