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Aneli [31]
2 years ago
9

How is an electromagnet different from a magnet?

Physics
1 answer:
RSB [31]2 years ago
5 0

Answer: b . An electromagnet can be changed by changing the amount of current.

Explanation:

In an <u>electromagnet</u>, <u>the magnetic field is generated by an electric current in a coil of wire which reinforces an iron core. But when the electric current applied on the mentioned core is disconnected, it immediately loses its magnetization</u>. This also means that the intensity of the magnetic field can be controlled (increased or decreased) by changing the intensity of the electric current flowing through the nucleus.

On the other hand, the <u>permanent magnet</u> <u>does not depend on electric current to magnetize</u>, because <u>due to its composition (a ferromagnetic material)</u> the magnetization capacity continues even after not being in contact with an external magnetic field.

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Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st
DedPeter [7]

Answer:

E1  = 10.15 * 10^4 N/C

E2 = 0

E3 = 10.15 *10^4 N/C

Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

charge (Q)  = +11nC

distance between thin glass rods   = 4 cm .

<u>Calculate the electric field strengths </u>

electric charge due to a single glass rod in the question ( E ) = \frac{Q}{2\pi e_{0}rL }

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = \frac{Q}{2\pi e_{0}rL } ( \frac{1}{0.01} - \frac{1}{0.03} )    ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )

   = \frac{11*10^{-9} }{2*3.14*8.85*10^{-12}*0.13 } ( 66.67 )

   = 10.15 * 10^4 N/C

applying equation 1 to determine E2

E2 = \frac{Q}{2\pi e_{0}rL }( \frac{1}{0.02} - \frac{1}{0.02} )

therefore E2 = 0

E1 = E3

hence E3 = 10.15*10^4 N/C

4 0
2 years ago
Why does a black hole have a stronger gravitational pull than the star that collapse to form it?​
Studentka2010 [4]

Answer:

We consider Black Holes as an object that possesses extreme gravitational pull, but wait aren’t they have the same mass(or less) as that of their parent star. And we know that gravitational pull ‘F’ is directly proportional to the mass of an object, so if the mass is same(or less) then why do black holes have stronger gravity than the stars they evolved from.

The above consideration that F is directly proportional to the mass is partially correct, one should also mention that F is also inversely proportional to the square of the distance between the considered objects.

F = G*(M*m)/(r^2)

Where:

· F is the force acting on you due to star

· M is the mass of Parent star / Black Hole

· m is the mass of an observer, here it is you

· r is the radial distance between the star and you

We know that black hole formed, has much smaller size than that of its parent star and all that mass is compressed to a much smaller scale. If you consider a Star as having a size of an earth then the black hole formed will have a size of small city.

Let us say that you are standing at an r distance away from a star (r>R1), where R1 is the radius of the star, of course (R1>R2), where R2 is the radius of Black Hole.

The Force by which the star in case 1 attracts you will be equal(or less) to the force by which black hole in case 2. So, there is nothing increase in gravitational pull, it is same(or less) as that of the parent star.

Wait a minute, then why people say that black holes have massive gravitational pull.

The gravitational pull increases as we move closer to the black hole, and when we are at its surface, it is enormous as compare to its star surface, because of the difference in the size.

We know that gravitational pull not only depends upon the mass but also depends upon the radial distance between the concerned objects here, it is you and the black hole.

Here, the size of the black hole is much smaller than that of its parent star, i.e (R1>>>R2), and thus we get F1<<<F2, and that is why we say that the black hole has enormous gravitational pull, such that nothing can escape, not even light.

8 0
2 years ago
A is a hot object.  B is a cold object.  the two are brought into contact with each other so that heat is developed
Umnica [9.8K]

Answer:

A) Cold object will start getting hot

B) Heat exchange will stop as the two object acquire the same temperature.

Explanation:

A) When one hot object and one cold object are kept in contact then the heat is transferred from the hot object to the cold object via different modes of heat transmission. Hence, the cold object starts getting hot

B) The transmission of heat from the hot object to the cold object will stop as the temperature of the two object becomes equal to each other.

3 0
3 years ago
In a rigid container, as the temperature of a gas decreases, the pressure of the gas will decrease. t f
Sergio039 [100]
The answer is true: the pressure of a gas will decrease as temperature decreases in a rigid container.

This is one of the central gas laws called the Gay-Lussac law that states for a given gas at a constant volume, the pressure of the gas is directly proportional to its temperature. We also know that as temperature reduces, so too does molecular interaction. Increased temperature results in increased pressure, and decreased temperature therefore results in decreased pressure.
6 0
3 years ago
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What is the nucleation mechanisms in which nuclei of the solid phase form in the interior of the liquid as atoms cluster togethe
pshichka [43]
I  think its q because i suck on toes 


8 0
2 years ago
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