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ch4aika [34]
3 years ago
7

A piano string having a mass per unit length equal to 4.70 10-3 kg/m is under a tension of 1 400 N. Find the speed with which a

wave travels on this string.
Physics
1 answer:
sweet [91]3 years ago
3 0

Answer:

The speed of the sound wave on the string is 545.78 m/s.

Explanation:

Given;

mass per unit length of the string, μ = 4.7 x 10⁻³ kg/m

tension of the string, T = 1400 N

The speed of the sound wave on the string is given by;

v = \sqrt{\frac{T}{\mu} }

where;

v is the speed of the sound wave on the string

Substitute the given values and solve for speed,v,

v = \sqrt{\frac{T}{\mu} }\\\\v = \sqrt{\frac{1400}{4.7*10^{-3}} }\\\\v = \sqrt{297872.34}\\\\v = 545.78 \ m/s

Therefore, the speed of the sound wave on the string is 545.78 m/s.

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tankabanditka [31]

The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

  • Electrical power = voltage × current

The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.

Total power dissipated = 5 × 2.5 = 12.5 Watts

  • Work done = power × time (in seconds)

Work done = 12.5 × (1 × 3600 + 15 × 60)

Work done = 56250 J = 56.25 kJ

Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

Learn more about electrical power and work done at: brainly.com/question/23901751

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The speed of S-waves is what percent of that of P-Waves?<br><br><br><br><br><br><br> Help plz
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3 0
3 years ago
6. You are in an airplane going down a runway currently going 24 m/s and accelerating at 8 m/s?
Allisa [31]

Answer:

The time taken by the airplane to take off, t = 11.46 s

Explanation:

Given data,

The initial velocity of the airplane, u = 24 m/s

The acceleration of the plane, a = 8 m/s

The distance covered until take off, d = 800 m

Using the III equation of motion,

                      v² = u² +2as

                           = 24² + 2 x 8 x 800

                           = 13376

                       v = 115.65 m/s

Using the first equation of motion,

                      v = u + at

                       t = (v-u) / a

                         = (115.65 - 24) / 8

                         = 11.46 s

Hence, the time taken by the airplane to take off, t = 11.46 s

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