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natali 33 [55]
3 years ago
8

Caroline conducts research on how the amount of fiber in a student's breakfast affects their grades in school. How should she re

present her data?
data table and line graph

data table and bar Graph

data table with no graphc

neither a data table nor a graph
Physics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer:

data table and line graph ( first choice)

steposvetlana [31]3 years ago
5 0

Answer:

data table and line graph

Explanation:

The data table would consist of the amount of fiber that a student consumes in one column and the grade of the student. So, here the independent variable is amount of fiber that a student consumes and the dependent variable is the grade of the student. The x axis of the graph represents the amount of fiber that a student consumes and the y axis represents the grade of the student.

The line in a graph represents the relationship between the variables of the graph.

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How can we realize that light travel in straight line ?​
Norma-Jean [14]

Answer:

It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.

Explanation:

The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.

One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light

Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.  

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3 years ago
Describe using examples how objects can be at rest and in motion simultaneously
elena-14-01-66 [18.8K]
An object can be at rest and still be in motion because the earth is always in motion.

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Meteorology is BEST defined as
alexgriva [62]
It is the branch of science, in which we study different phenomena of atmosphere including climate and weather.
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3 years ago
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Calculate curls of the following vector functions (a) AG) 4x3 - 2x2-yy + xz2 2
aleksandr82 [10.1K]

Answer:

The curl is 0 \hat x -z^2 \hat y -4xy \hat z

Explanation:

Given the vector function

\vec A (\vec r) =4x^3 \hat{x}-2x^2y \hat y+xz^2 \hat z

We can calculate the curl using the definition

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\A_x&X_y&A_z\end{array}\right|

Thus for the exercise we will have

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\4x^3&-2x^2y&xz^2\end{array}\right|

So we will get

\nabla  \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z

Working with the partial derivatives we get the curl

\nabla  \times \vec A (\vec r )=0 \hat x -z^2 \hat y -4xy \hat z

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3 years ago
All of the waves in the electromagnetic spectrum are _______ waves.
user100 [1]
Transverse, I think. I may be wrong.
5 0
3 years ago
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