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Elden [556K]
3 years ago
10

An organic compound in which a carbonyl group is bonded to two different carbon atoms is a(n) amide. aldehyde. ketone. ester.

Chemistry
2 answers:
77julia77 [94]3 years ago
4 0
An organic compound in which a carbonyl group is bonded to two different carbon atoms is a ketone. The ketones are organic compounds in which a carbonyl group (C=O) is bonded to two carbon atom. A carbonyl group is a carbon-oxygen double bond. Ketones are of great importance in industry and in biology, <span>as solvents, polymer precursors, and pharmaceuticals.</span>
Anton [14]3 years ago
3 0

Answer: ketone

Explanation:

Functional groups are specific group of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.

1. Amides have functional group -O=C-NH_2.

Example: Ethanamide with molecular formula CH_3CONH_2

2. Aldehydes have functional group -O=CH.

Example: Ethanal with molecular formula CH_3CHO

3. Ketones have functional group -C=O.

Example: Propanone with molecular formula CH_3COCH_3

4. Esters have functional group -O=C-OR.

Example: methyl ethanoate with molecular formula CH_3COOCH_3

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What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N
Citrus2011 [14]
<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.22 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{1 \ mol \ Mg_3N_2}{3 \ mol \ Mg})(\frac{100.95 \ g \ Mg_3N_2}{1 \ mol\ Mg_3N_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 1.68873 \ g \ Mg_3N_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

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