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3 years ago

An organic compound in which a carbonyl group is bonded to two different carbon atoms is a(n) amide. aldehyde. ketone. ester.

2 answers:

4 0

An organic compound in which a carbonyl group is bonded to two different carbon atoms is a ketone. The ketones are organic compounds in which a carbonyl group (C=O) is bonded to two carbon atom. A carbonyl group is a carbon-oxygen double bond. Ketones are of great importance in industry and in biology, <span>as solvents, polymer precursors, and pharmaceuticals.</span>

Anton [14]3 years ago

3 0

Answer: ketone

Explanation:

Functional groups are specific group of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.

1. Amides have functional group $-O=C-NH_2$ .

Example: Ethanamide with molecular formula $CH_3CONH_2$

2. Aldehydes have functional group $-O=CH$ .

Example: Ethanal with molecular formula $CH_3CHO$

3. Ketones have functional group $-C=O$ .

Example: Propanone with molecular formula $CH_3COCH_3$

4. Esters have functional group $-O=C-OR$ .

Example: methyl ethanoate with molecular formula $CH_3COOCH_3$

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Paladinen [302]

The process to create a protected area takes a long time because there's numerous things that have to be taken in account and sorted out before the area gets that kind of legal status.

Usually there's people living in the area that is supposed to be protected, though it is mostly small settlements. The people living there are connected with that area, use the resources, and their lives are largely based and dependent on it. In order for any problems to be avoided, these people should all be educated, deals to be made with them, and properly negotiated so that the area wouldn't have any damage, but also them to be able to sustain themselves.

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3 years ago

An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar

Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

$372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s$

= 4526 g/s

Now, we will calculate the power as follows.

Power = Fuel consumption rate × -enthalpy of combustion

= $4526 g/s \times -26.5 kJ/g$

= $1.19 \times 10^{5}$ kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is $1.19 \times 10^{5}$ kW.

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3 years ago

How much energy is required to change the temperature of 50g of water from 20 C to 55 C?

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3 years ago

Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. Δ H°(kJ) Ca(s)→Ca(g) 1

Drupady [299]

Answer : The value of second ionization energy of Ca is 1010 kJ.

Explanation :

The formation of calcium oxide is,

$Ca(s)+\frac{1}{2}O_2(g)\overset{\Delta H_f}\rightarrow CaO(s)$

$\Delta H_f^o$ = enthalpy of formation of calcium oxide = -635 kJ

The steps involved in the born-Haber cycle for the formation of $CaO$ :

(1) Conversion of solid calcium into gaseous calcium atoms.

$Ca(s)\overset{\Delta H_s}\rightarrow Ca(g)$

$\Delta H_s$ = sublimation energy of calcium = 193 kJ

(2) Conversion of gaseous calcium atoms into gaseous calcium ions.

$Ca(g)\overset{\Delta H_I_1}\rightarrow Ca^{+1}(g)$

$\Delta H_I_1$ = first ionization energy of calcium = 590 kJ

(3) Conversion of gaseous calcium ion into gaseous calcium ions.

$Ca^{+1}(g)\overset{\Delta H_I_2}\rightarrow Ca^{+2}(g)$

$\Delta H_I_2$ = second ionization energy of calcium = ?

(4) Conversion of molecular gaseous oxygen into gaseous oxygen atoms.

$O_2(g)\overset{\Delta H_D}\rightarrow OI(g)$

$\frac{1}{2}O_2(g)\overset{\Delta H_D}\rightarrow O(g)$

$\Delta H_D$ = dissociation energy of oxygen = $\frac{498}{2}=249kJ$

(5) Conversion of gaseous oxygen atoms into gaseous oxygen ions.

$O(g)\overset{\Delta H_E_1}\rightarrow O^-(g)$

$\Delta H_E_1$ = first electron affinity energy of oxygen = -141 kJ

(6) Conversion of gaseous oxygen ion into gaseous oxygen ions.

$O^-(g)\overset{\Delta H_E_2}\rightarrow O^{2-}(g)$

$\Delta H_E_2$ = second electron affinity energy of oxygen = 878 kJ

(7) Conversion of gaseous cations and gaseous anion into solid calcium oxide.

$Ca^{2+}(g)+O^{2-}(g)\overset{\Delta H_L}\rightarrow CaO(s)$

$\Delta H_L$ = lattice energy of calcium oxide = -3414 kJ

To calculate the overall energy from the born-Haber cycle, the equation used will be:

$\Delta H_f^o=\Delta H_s+\Delta H_I_1+\Delta H_I_2+\Delta H_D+\Delta H_E_1+\Delta H_E_2+\Delta H_L$

Now put all the given values in this equation, we get:

$-635kJ=193kJ+590kJ+\Delta H_I_2+249kJ+(-141kJ)+878kJ+(-3414kJ)$

$\Delta H_I_2=1010kJ$

Therefore, the value of second ionization energy of Ca is 1010 kJ.

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3 years ago

A light-year is the distance that light travels in one year. Please select the best answer from the choices provided T F

german

Answer:True

Explanation:

Light year is the unit of distance and not a unit of time.

Light year is used to measure astronomical distances.

It is defined as the distance which light travels in one year.

The distance which light travels in one year is around 9.46 trillion kilometers

Thus 1 light year = $9.46\times 10^9$ km.

Thus the given statement that A light-year is the distance that light travels in one year is true.

7 0

3 years ago

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