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katen-ka-za [31]
2 years ago
5

2. Each of the bracelets that Veronica made has 45 beeds. Shemede 4 bracelets.

Mathematics
2 answers:
Ann [662]2 years ago
7 0

Answer:

180 total beads used

Step-by-step explanation:

=) have a good day

cluponka [151]2 years ago
6 0
She used 180 beads because 45x4 =180
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What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

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2 years ago
Here is free points FOR BEINGS NERDS
Maurinko [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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vovikov84 [41]
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4 0
3 years ago
Read 2 more answers
Hector can paint (128
marysya [2.9K]

Answer:

16

Step-by-step explanation:

128/8= 16

8 0
3 years ago
Ritu is travelling by a car at a speed of
faltersainse [42]

Answer:

40 min is the answer

Step-by-step explanation:

To solve this we need to convert all the units into SI units

for ritu,

speed= 90km/hr

= 90 × 1km/ 1hour

= 90×1000/3600 m/s

= 25m/s

distance = 120×1000m

time = distance/ speed

= 120000/25

= 4800sec

= 4800/60min

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for garima,

distance =120×1000m

speed = 60km/hr

= 60×1000/3600 m/s

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time = 120000/(100÷6)

= 7200sec

= 7200÷60 min

= 120 min

time difference is 120-80 = 40 min

4 0
2 years ago
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