To cut down on injuries, a highway guardrail is designed to be moved a maximum of 0.05 meters when struck by a car. What is the
1 answer:
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Answer:
2.36 μ H
Explanation:
Given,
Number of turns= 90
diameter = 1.3 cm = 0.013 m
unscratched length = 57 cm = 0.57 m
Area, A = π r²
= π x 0.0065² = 1.32 x 10⁻⁴ m²
we know,
L = 2.36 μ H
Hence, the inductance of the unstretched cord is equal to 2.36 μ H
The kinetic energy halfway the hill is
Explanation:
If there are no friction forces acting on the cart, we can apply the law of conservation of energy: the mechanical energy of the cart (which is the sum of potential energy + kinetic energy) must be conserved. So we can write:
where
is the initial potential energy, at point A, with
m = 980 kg (mass of the cart)
(acceleration of gravity)
(height at point A)
is the initial kinetic energy, at point A
, with
(velocity at point A)
is the final potential energy, at point B, where
(height at point B)
is the final kinetic energy, at point B, where
is the velocity at point B
Here we are interested in finding , so by re-arranging the equation and substituting we find:
Learn more about kinetic energy:
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