Answer:
Explanation:
the net force on the right left is 25 N and is directed upward
the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero
i hope this will help you
Answer:
a) 6.95 m/s
b) 1.42 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
![v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow -u^2=2\times -9.81\times 2.46-0^2\\\Rightarrow u=\sqrt{2\times 9.81\times 2.46}\\\Rightarrow u=6.95\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20-u%5E2%3D2as-v%5E2%5C%5C%5CRightarrow%20-u%5E2%3D2%5Ctimes%20-9.81%5Ctimes%202.46-0%5E2%5C%5C%5CRightarrow%20u%3D%5Csqrt%7B2%5Ctimes%209.81%5Ctimes%202.46%7D%5C%5C%5CRightarrow%20u%3D6.95%5C%20m%2Fs)
a) The vertical speed when it leaves the ground. is 6.95 m/s
![v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-6.95}{-9.81}\\\Rightarrow t=0.71\ s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20t%3D%5Cfrac%7Bv-u%7D%7Ba%7D%5C%5C%5CRightarrow%20t%3D%5Cfrac%7B0-6.95%7D%7B-9.81%7D%5C%5C%5CRightarrow%20t%3D0.71%5C%20s)
Time taken to reach the maximum height is 0.71 seconds
![s=ut+\frac{1}{2}at^2\\\Rightarrow 2.46=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.46\times 2}{9.81}}\\\Rightarrow t=0.71\ s](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%202.46%3D0t%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.81%5Ctimes%20t%5E2%5C%5C%5CRightarrow%20t%3D%5Csqrt%7B%5Cfrac%7B2.46%5Ctimes%202%7D%7B9.81%7D%7D%5C%5C%5CRightarrow%20t%3D0.71%5C%20s)
Time taken to reach the ground from the maximum height is 0.71 seconds
b) Time it stayed in the air is 0.71+0.71 = 1.42 seconds
Answer:
The deformation is 0.088289 m
The final height of the monument is 170-0.088289 = 169.911702 m
Explanation:
Thermal coefficient of marble varies between (5.5 - 14.1) ×10⁻⁶/K = α
So, let us take the average value
(5.5+14.1)/2 = 9.8×10⁻⁶ /K
Change in temperature = 35-(-18) = 53 K = ΔT
Original length = 170 m = L
Linear thermal expansion
![\frac{\Delta L}{L} = \alpha\Delta T\\\Rightarrow \Delta L=\frac{\alpha\Delta T}{L}\\\Rightarrow \Delta L=9.8\times 10^{-6}\times 53\times 170](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20L%7D%7BL%7D%20%3D%20%5Calpha%5CDelta%20T%5C%5C%5CRightarrow%20%5CDelta%20L%3D%5Cfrac%7B%5Calpha%5CDelta%20T%7D%7BL%7D%5C%5C%5CRightarrow%20%5CDelta%20L%3D9.8%5Ctimes%2010%5E%7B-6%7D%5Ctimes%2053%5Ctimes%20170)
The deformation is 0.088289 m
The final height of the monument is 170-0.088289 = 169.911702 m (subtraction because of cooling)
Answer with Explanation:
We are given that
Magnetic field,B=![0.6\times 10^{-4} T](https://tex.z-dn.net/?f=0.6%5Ctimes%2010%5E%7B-4%7D%20T)
![\theta=75^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D75%5E%7B%5Ccirc%7D)
Length of wire,l=15 m
Current,I=19 A
a.We have to find the magnitude of magnetic force and direction of magnetic force.
Magnetic force,F=![IBlsin\theta](https://tex.z-dn.net/?f=IBlsin%5Ctheta)
Using the formula
![F=0.6\times 10^{-4}\times 15\times 19sin75](https://tex.z-dn.net/?f=F%3D0.6%5Ctimes%2010%5E%7B-4%7D%5Ctimes%2015%5Ctimes%2019sin75)
![F=16.5\times 10^{-3} N](https://tex.z-dn.net/?f=F%3D16.5%5Ctimes%2010%5E%7B-3%7D%20N)
Direction=![tan\theta=cot(90-75)=tan15^{\circ}](https://tex.z-dn.net/?f=tan%5Ctheta%3Dcot%2890-75%29%3Dtan15%5E%7B%5Ccirc%7D)
![\theta=15^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D15%5E%7B%5Ccirc%7D)
15 degree above the horizontal in the northward direction.