To cut down on injuries, a highway guardrail is designed to be moved a maximum of 0.05 meters when struck by a car. What is the
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Answer:
a) Initial Value Problem
dv/dt = 4 - 0.1v
v(0) = 0
b) solution to the IVP
v(t) = 40(1 - e^(-t/10))
c) Limiting velocity
Vo = 40 ft/s
Position of the car after 12 hours
X = 14,390 ft
Explanations:
The complete explanations of each of the sections contained in the question are in the files attached to this solution.
.75(m/s)^2
Use this picture
If you know the two on the bottom you multiply them but if you only know the top and one on the bottom you divide
Use this picture
If you know the two on the bottom you multiply them but if you only know the top and one on the bottom you divide