3 years ago

On his way to school, a student starts out walking quickly and then slows down as he gets closer to the school. Which graph best

Physics

2 answers:

ololo11 [35]3 years ago

6 0

I believe the answer is a. It shows an increase in the beginning but slowly starts to remain constant

Leni [432]3 years ago

3 0

' A ' is the graph that shows it.

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Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the

erma4kov [3.2K]

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

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2 years ago

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Why are newtons second and third law important to everyday life?

Rzqust [24]

Because it always happens everyday, everytime, everyseconds...
Like typing on a keyboard, pushing a table. And if you're an engineer, you must able to measure it...
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2 years ago

Describe what it means to view something from a frame of reference.Give an example to illustrate your explanation.

Roman55 [17]

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2 years ago

A hoop (I = MR2) of mass 3 kg and radius 1.1 m is rolling at a center-of-mass speed of 11 m/s. An external force does 842 J of w

Scilla [17]

Answer:

$v_f = 20 m/s$

Explanation:

Since the hoop is rolling on the floor so its total kinetic energy is given as

$KE = \frac{1}{2}mv^2 + \frac{1}{2} I\omega^2$

now for pure rolling condition we will have

$v = R\omega$

also we have

$I = mR^2$

now we will have

$KE = \frac{1}{2}mv^2 + \frac{1}{2}(mR^2)\frac{v^2}{R^2}$

$KE = mv^2$

now by work energy theorem we can say

$W = KE_f - KE_i$

$842 J = mv_f^2 - mv_i^2$

$842 = 3(v_f^2) - 3\times 11^2$

now solve for final speed

$v_f = 20 m/s$

3 0

2 years ago

A book starts on a shelf 1 m off of the ground. You then move the book to a higher shelf that is 3 m off of the ground. If the s

JulsSmile [24]

Answer:

Using g = 9.8: 1.02 kg, Using g = 10: 1 kg

Explanation:

E = mgh

20 = m(9.8)(3 - 1)

20 = 9.8m(2)

20 = 19.6m

m = 1.02 kg

I'm now assuming you may be using a g constant of 10, thus the close integer result, in which case the mass would be exactly 1 kilogram.

4 0

3 years ago