( 1.05 x 10¹⁵ km ) x ( 1 LY / 9.5 x 10¹² km ) x ( 1 psc / 3.262 LY ) =
(1.05) / (9.5 x 3.262) x (km · LY · psc) / (km · LY) x (10¹⁵⁻¹²) =
(0.03388) x (psc) x (10³) =
33.88 parsecs
Sorry I had the answer but it wont let me type numbers :(.:
Answer:
Force / mass
Explanation:
Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass
angular vel to tangential vel
v=r omega
v = 56 x 100/60 x 2 pi
v = 56x5/3x6
v=560m/s as estimate
100 revs, 5.00m
Answer: d. I or II
Explanation: A traveling wave has speed that depends on characteristics of a medium. Characteristics like linear density (μ), which is defined as mass per length.
Tension or Force (
) is also related to the speed of a moving wave.
The relationship between tension and linear density and speed is ginve by the formula:

So, for the traveling waves generated on a string fixed at both ends described above, ways to increase wave speed would be:
1) Increase Tension and maintaining mass and length constant;
2) Longer string will decrease linear density, which will increase wave speed, due to their inversely proportional relationship;
Then, ways to increase the wave speed is
I. Using the same string but increasing tension
II. Using a longer string with the same μ and T.