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igomit [66]
3 years ago
10

You place a drop of blue food coloring in a cup of cold water and another drop of food coloring in a cup of hot water. Which obs

ervation is correct and why? A The food coloring in the hot water will spread more slowly than in the cold water because water molecules move more slowly when hot. B The food coloring in the hot water will spread more quickly than in the cold water because water molecules move more quickly when hot. C The food coloring in the cold water will spread more quickly than in the hot water because water molecules move more quickly when cold. D The food coloring in the cold water will spread at the same rate at the food coloring in the hot water because water molecules at any temperature move at the same rate.
Physics
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

B food coloring will move quicker in hot water because the molecules move faster when they are hot

Explanation:

SCIENCE! aaaaand my physics text book

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You are on a ParKour course. First you climb a angled wall up 9.5 meters. They you shimmy along the edge of a 3.5 meter long wal
Svet_ta [14]

The average speed would be  0.65 m/s, therefore the correct option is (A).

The average speed is calculated by the formula

Average speed= (total distance/ total time)

The total distance of the trip=9.5+3.5+15=28 m

The total time of trip=43 sec

Therefore the average speed=28/43=0.65 m/s.


8 0
3 years ago
A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
RideAnS [48]

Answer:

Explanation:

Initial kinetic energy of M = 1/2 M vi²

let final velocity be vf

v² = u² + 2a s

vf² =  vi² + 2 (F / M) x D

Kinetic energy

= 1/2 Mvf²

= 1/2 M ( vi² + 2 (F / M) x D

1/2 M vi² + FD

Ratio with initial value

1/2 M  vi² + FD) / 1/2 M  vi²

RK = 1 + FD / 2 M  vi²

4 0
3 years ago
Martina seems to have several different personalities. In one, she is 7 years
melomori [17]

Answer:Dissociative Identity Disorder

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3 0
3 years ago
Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field
Katyanochek1 [597]

Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength  at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength  at the midpoint between the two rings is given as;

E_{mid} = E_{right} +E_{left}\\\\E_{right}  = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt}  = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }  - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0

Therefore, the electric field strength at the mid-point between the two rings is zero.

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Answer:

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