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3 years ago

5

Specialized visual receptors that assist mostly in nighttime vision are __________. A. cones B. rods C. fovea D. optic disks Ple

ase select the best answer from the choices provided A B C D

2 answers:

maw [93]3 years ago

4 0

Answer:

B: rods

Explanation:

got it right on assignment.

Aleonysh [2.5K]3 years ago

3 0

Answer:

B

Explanation:

EDGE 2020

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What charge accumulates on the plates of a 2.0-μF air-filled capacitor when it is charged until the potential difference across

enot [183]

Answer:

0.0002 C.

Explanation:

Charge: This can be defined as the ratio of current to time flowing in a circuit. The S.I unit of charge is Coulombs (C)

Mathematically, charge can be expressed as

Q = CV ................................. Equation 1

Where Q = amount of charge, C = capacitance of the capacitor, V = potential difference across the plates.

Given: C = 2.0-μF = 2×10⁻⁶ F, V = 100 V.

Substitute into equation 1

Q = 2×10⁻⁶× 100

Q = 2×10⁻⁴ C

Q = 0.0002 C.

The amount of charge accumulated = 0.0002 C

7 0

3 years ago

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Rank the following in terms of increasing inertia:

Naddik [55]

C. A 1200kg car is going 15m/s

7 0

3 years ago

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A 1000.kg car moving at north at 100. km/hr brakes to a stop in 50. m within a uniform acceleration. what are magnitude and dire

Marianna [84]

Answer:

Force=7.71KN in the opposite direction

Explanation:

Given the mass of the car(M)=1000Kg

The initial speed of the car(u)=100km/hr

we know that 1km/hr=5/18 m/sec

100km/hr=100*5/18 m/sec=27.77m/sec

the distance travelled before it stops (s)=50m

let the acceleration of the car be a

The final velocity of the car is 0.

we know that $v^{2}-u^{2}=2as$

$0^{2}-27.77^{2}=2(-a)(50)$

a=7.712m/ $sec^{2}$

We know that F=Ma

F=1000* 7.712=7712N=7.71KN

6 0

3 years ago

In the year 2000, a company made $4.7 million in profit. For each consecutive year after that, their profit increased by 15%. Ho

olya-2409 [2.1K]

Answer: $8.2 million.

Explanation:

If we have a quantity A, and we have an increase of x%, this can be written as:

A + (x%/100%)*A

Now, for this particular case we have:

In year 2000 (we can define this year as the year zero, y = 0) the initial value is $4.7 million.

The next year, y = 1, there is an increase of 15%, then we will have a profit of:

P = $4.7 million + (15%/100%)*$4.7 million = $4.7 million + 0.15*$4.7 million

P = $4.7 million*(1 + 0.15) = $4.7 million*(1.15)

in the next year, y = 2, the profit will be:

P = $4.7 million*(1.15) + (15%/100%)* $4.7 million*(1.15)

= $4.7 million*(1.15) + 0.15* $4.7 million*(1.15)

= $4.7 million*(1.15)^2

We already can see the pattern, the profit in the year y will be:

P(y) = $4.7 million*(1.15)^y

In particular, in the year 2004 we have y = 4, then the profit that year will be:

P(4) = $4.7 million*(1.15)^4 = $8.2 million.

8 0

3 years ago

Three uses of concave lens

Nina [5.8K]

Answer:

used in telescope, glasses, cameras, flashlights, peepholes

Explanation:

Concave lens curve inward so they cause light to spread out.

6 0

3 years ago