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shutvik [7]
4 years ago
5

Specialized visual receptors that assist mostly in nighttime vision are __________. A. cones B. rods C. fovea D. optic disks Ple

ase select the best answer from the choices provided A B C D
Physics
2 answers:
maw [93]4 years ago
4 0

Answer:

B: rods

Explanation:

got it right on assignment.

Aleonysh [2.5K]4 years ago
3 0

Answer:

B

Explanation:

EDGE 2020

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A solid cylindrical object has a mass of 2.0 kg, a diameter
omeli [17]

Answer:

I = 0.0025 kg.m²

Explanation:

Given that

m= 2 kg

Diameter ,d= 0.1 m

Radius ,R=\dfrac{d}{2}

R=\dfrac{0.1}{2}

R=0.05 m

The moment of inertia of the cylinder about it's axis same as the disc and it is given as

I=\dfrac{mR^2}{2}

Now by putting the all values

I=\dfrac{2\times 0.05^2}{2}

I = 0.0025 kg.m²

Therefore we can say that the moment of inertia of the cylinder will be  0.0025 kg.m².

4 0
3 years ago
An underwater diver sees the sun 50° above horizontal. how high is the sun above the horizon to a fisherman in a boat above the
Usimov [2.4K]
Snell's law states that:

n1 Sin∅1 = n2 Sin ∅2

Where, medium 1 with (n1 = 1.33) is water and medium 2 with (n2 = 1) is the air, ∅1 = 90-50 = 40°

Therefore,
Sin ∅2 = n1/n2 *Sin ∅1 = 1.33/1 *Sin 40 = 0.4833=> ∅1 = Sin ^- (0.4833) = 28.9 °

The fisherman the sun at 61.1° (90-∅2) above the horizontal.
3 0
3 years ago
The weight of an object on a planet depends not only on its mass but also on its distance from the planets center this table lis
Korvikt [17]

You just pointed out that the gravitational force also depends
on the distance from the planet's center. The radius of Uranus
is about 4 times the Earth's radius.  That fact alone means that
the gravitational force on the surface is 1/4² = 1/16 its value on
Earth's surface.  So increasing the planet's mass by a factor of
14 doesn't compensate for the 1/16 reduction, and the gravitational
force on Uranus is less than on Earth.

4 0
3 years ago
A 650-kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruis- ing speed
Nataly_w [17]

Answer: P=5573.43\ W

Explanation:

Given

Mass of the elevator is M=650\ kg\\\

Time period of ascension t=3\ s

cruising speed v=1.75\ m/s

Distance moved by elevator during this time

Suppose Elevator starts from rest

\Rightarrow v=u+at\\\Rightarrow 1.75=0+a(3)\\\Rightarrow a=0.583\ s

Distance moved

\Rightarrow h=ut+0.5at^2\\\Rightarrow h=0+0.5\times 0.5833\times (3)^2\\\Rightarrow h=2.62\ m

Gain in Potential Energy is

\Rightarrow E=mgh\\\Rightarrow E=650\times 9.8\times 2.62\\\Rightarrow E=16,720.3\ N

Average power during this period is

\Rightarrow P=\dfrac{E}{t}\\\\\Rightarrow P=\dfrac{16,720.3}{3}\\\\\Rightarrow P=5573.43\ W

7 0
3 years ago
Read 2 more answers
a 75-kg refrigerator is located on the 70th floor of a skyscraper (300 meters above the ground) what is the potential energy of
kiruha [24]
The gravitational potential energy of an object depends on three things. Its mass, its height above the surface of the earth and the pull of gravity (which is assumed to always be 9.8 m/s².

The Formula for finding the GPE is : m x g x h where m = mass, g = gravitational acceleration and h is height from earth's surface. 

Using this formula we can find that :
GPE= 75 x 9.8 x 300 = 220500J (where J is the SI unit for GPE and stands for Joules.
6 0
4 years ago
Read 2 more answers
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