Answer:
Time, t = 0.23 seconds
Explanation:
It is given that,
Initial speed of the ranger, u = 52 km/h = 14.44 m/s
Final speed of the ranger, v = 0 (as brakes are applied)
Acceleration of the ranger, 
Distance between deer and the vehicle, d = 87 m
Let d' is the distance covered by the deer so that it comes top rest. So,
d' = 26.06 m
Distance between the point where the deer stops and the vehicle is :
D=d-d'
D=87 - 26.06 = 60.94 m
Let t is the maximum reaction time allowed if the ranger is to avoid hitting the deer. It can be calculated as :
t = 0.23 seconds
Hence, this is the required solution.
A = -9.8
v = -9.8t -8
s = -4.9 t2 -8t +25
So… -5t^2 -8t + 25 =0, we’ll rearrange to 5t^2 + 8t - 25. We get two roots, one is positive and is 1.59 seconds
V = -9.8(1.59) - 8 = -23.6
So… it takes 1.59 seconds to hit the ground at -23.6 m/s.
To determine the object which could give the greatest impact we will apply the concept of momentum. The object that has the highest momentum will be the object that will impact the strongest. Our values are
Mass of Object A
Velocity of object A
Mass of object B
Velocity of object B
The general formula for momentum is the product between mass and velocity, then
For each object we have then,
Since the momentum of object A is greater than that of object B, then object A will make you feel force upon impact.
Temperatures can cause matter to change state.
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