Find the surface area of the prism or pyramid. Round to the nearest whole number if necessary.

Cindy has 6 identical pink candies and 8 identical green candies. Find the number of ways that Cindy can line up her candies in

Daniel [21]

Answer:

175 ways

Step-by-step explanation:

Form a partition into 2 or 3 parts and the number of ways.

Pink candies

[1,5](2) , [2,4](2) , [3,3](1) , [1,4](3), [1,2,3](6) , [2,2,2](1)

Green candies

[1,7](2) , [2,6](2) , [3,5](2) , [4,4](1) , [1,1,6](3) , [1,2,5](6) , [1,3,4](6) , ,[2,2,4](3) , [2,3,3](3)

Number of ways will be:

(2+2+1) (2+6+6+3+3) + (3+6+1)(2+2+2+1)

Number of ways =( 5×21) + (10×7) = 175ways

4 0

3 years ago

Find the inequality represented by the graph

xeze [42]

Answer:

88

Step-by-step explanation:

3 0

3 years ago

I need help in area it's hard

Fofino [41]

The area is the length times the width. Find area of shapes by counting unit squares. Some shapes will require combining partial square units to find area.

For example - A rectangle is 5 centimeters long and 4 centimeters wide. What is its area? 

Area = Length * width

The length is 5 centimeters. The width is 4 centimeters. So the area is 5 times 4 square centimeters.

= 20 square centimeters

4 0

3 years ago

Lanie works part-time at Sweet Treats Catering. She earns $13.25 per hour and work 25 hours a

agasfer [191]

Answer:

Semi-monthly gross pay = $662.5

Step-by-step explanation:

Given:

Earning per hour = $13.25

Number of hours per week = 25 hours

Find:

Semi-monthly gross pay

Computation:

Assume two week in semi-month

So,

Total working hour = 2(25)

Total working hour = 50 hours

Semi-monthly gross pay = Total working hour × Earning per hour

Semi-monthly gross pay = 50 × 13.25

Semi-monthly gross pay = $662.5

8 0

3 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$