Emilio pushes a 100 kg freshman with 200 N of force. How much is the freshman accelerated?
1 answer:
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Answer:
The tension in the rope is 41.38 N.
Explanation:
Given that,
Mass of bucket of water = 14.0 kg
Diameter of cylinder = 0.260 m
Mass of cylinder = 12.1 kg
Distance = 10.7 m
Suppose we need to find that,
What is the tension in the rope while the bucket is falling
We need to calculate the acceleration
Using relation of torque
Where, I = moment of inertia
= angular acceleration
...(I)
Here, F = tension
The force is
...(II)
Where, F = tension
a = acceleration
From equation (I) and (II)
Put the value into the formula
We need to calculate the tension in the rope
Using equation (I)
Put the value into the formula
Hence, The tension in the rope is 41.38 N.
Answer:
The horizontal force is 106.89 N.
Explanation:
Given that,
Work done = 310 J
Distance = 2.9 m
We need to calculate the horizontal force
Using formula of work done
Where,
Put the value into the formula
Hence, The horizontal force is 106.89 N.