Emilio pushes a 100 kg freshman with 200 N of force. How much is the freshman accelerated?

que ventajas e inconvenientes tienen las energias renovables, el agua del mar, agua embalzada, el sol, el viento

ahrayia [7]

Answer:

Ventajas ambientales:

La principal ventaja es la prácticamente es nula la emisión de gases de efecto invernadero (GEI).

* Ayudan a disminuir enfermedades relacionadas con la contaminación.

* No necesitan grandes cantidades de agua para su funcionamiento.

* No crean problemas de basura difíciles de resolver, como la eliminación de residuos nucleares o escorias.

Ventajas económicas:

*Generación de empleos directos (trabajadores de la construcción, desarrolladores, fabricantes de equipo, diseñadores, instaladores, financieros).

* Competencia y reducción de precios de las generadoras tradicionales por tener un nuevo competidor, que asegure confiabilidad del servicio.

ENERGÍA SOLAR INCONVENIENTES:

La instalación de paneles solares en casas o industrias no es barato, además no todas las vivienda pueden instalarse este tipo de paneles. La legislación en cuanto al uso de los paneles solares no es la misma en todo el mundo.

ENERGÍA EÓLICA INCONVENIENTES:

La creación de parques eólicos es muy cara, además hay colectivos que se opinen a la instalación de parques eólicos en tierra porque opinan que afea el paisaje y es peligrosos para las aves que chocan al volar cerca de las hélices de los generadores eólicos.

ENERGÍA DE LAS MAREAS INCONVENIENTES:

El movimiento de las mareas mueve las turbinas. El movimiento de las mareas es capaz de mover turbinas, pero para ello hay que construir represas o aluviones.

Entre los inconvenientes está que la construcción de aluviones es muy cara. Hay oposición de grupos ecologistas que destacan que esta energía puede tener un impacto negativo sobre la fauna acuática. La energía de las mareas puede reducir el flujo de las mareas e impedir el flujo de aguas residuales al mar.

Explanation:

5 0

3 years ago

observe the figure given carefully volume of water in each vessel is shown arrange them in order of decreasing pressure at the b

mihalych1998 [28]

Answer:

See the explanation below

Explanation:

The pressure is defined as the product of the density of the liquid by the gravitational acceleration by the height, and can be easily calculated by means of the following equation.

$P=Ro*g*h$

where:

Ro = density of the fluid [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation [m]

In this way we can understand that the greater pressure is achieved by means of the height of the liquid, that is, as long as the fluid has more height, greater pressure will be achieved at the bottom.

Therefore in order of decreasing will be

The largest pressure with the largest height of the liquid, container B. The next is obtained with container D, the next with container A and the lowest pressure with container C.

The pressure decreases as we go from the container B - D - A - C

5 0

3 years ago

Estimate the boiling point of water at a pressure of 1.1 atmosphere

Nezavi [6.7K]

It is about 100oC at a pressure of 1.1 atmosphere. Hope this helps.

4 0

3 years ago

Instead of moving back and forth, a conical pendulum moves in a circle at constant speed as its string traces out a cone (see fi

tigry1 [53]

Answer:

a

The radial acceleration is $a_c = 0.9574 m/s^2$

b

The horizontal Tension is $T_x = 0.3294 i \ N$

The vertical Tension is $T_y =3.3712 j \ N$

Explanation:

The diagram illustrating this is shown on the first uploaded

From the question we are told that

The length of the string is $L = 10.7 \ cm = 0.107 \ m$

The mass of the bob is $m = 0.344 \ kg$

The angle made by the string is $\theta = 5.58^o$

The centripetal force acting on the bob is mathematically represented as

$F = \frac{mv^2}{r}$

Now From the diagram we see that this force is equivalent to

$F = Tsin \theta$ where T is the tension on the rope and v is the linear velocity

So

$Tsin \theta = \frac{mv^2}{r}$

Now the downward normal force acting on the bob is mathematically represented as

$Tcos \theta = mg$

So

$\frac{Tsin \ttheta }{Tcos \theta } = \frac{\frac{mv^2}{r} }{mg}$

=> $tan \theta = \frac{v^2}{rg}$

=> $g tan \theta = \frac{v^2}{r}$

The centripetal acceleration which the same as the radial acceleration of the bob is mathematically represented as

$a_c = \frac{v^2}{r}$

=> $a_c = gtan \theta$

substituting values

$a_c = 9.8 * tan (5.58)$

$a_c = 0.9574 m/s^2$

The horizontal component is mathematically represented as

$T_x = Tsin \theta = ma_c$

substituting value

$T_x = 0.344 * 0.9574$

$T_x = 0.3294 \ N$

The vertical component of tension is

$T_y = T \ cos \theta = mg$

substituting value

$T_ y = 0.344 * 9.8$

$T_ y = 3.2712 \ N$

The vector representation of the T in term is of the tension on the horizontal and the tension on the vertical is

$T = T_x i + T_y j$

substituting value

$T = [(0.3294) i + (3.3712)j ] \ N$

3 0

3 years ago

In one experiment, the students allow the block to oscillate after stretching the spring a distance A. If the potential energy s

atroni [7]

Answer:

K = m g (A - A2)

Explanation:

In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

Em = K + U₂

K = Em –U₂

We substitute

K = m g A - m gA2

K = m g (A - A2)

3 0

4 years ago

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