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sladkih [1.3K]
3 years ago
11

Doubling the amplitude of a wave means that you increase the ___ of a wave factor of _______

Chemistry
1 answer:
Nesterboy [21]3 years ago
5 0
Doubling the amplitude of a wave means that you increase the energy of a wave factor of quadrupling
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Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a s
disa [49]

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

[SO₄²⁻] = 0.037 M;

[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid.  HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R   HSO_4^-    ⇄  H^+ + SO_4^2^-

I    0.14

C   - x               +x       +x

E   0.14-x        x         x

K_a = 1.3 × 10^-^2 for HSO^-_4 . As a result,

\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a

K_a is large. It is no longer valid to approximate that [HSO^-_4] at equilibrium is the same as its initial value.

\frac{x^2}{0.14-y} = 1.3 * 10^-^2

x^2+1.3*10^-^2x - 0.14 × 1.3 × 10^-^2= 0

Solving the quadratic equation for x , x \geq 0 since x represents a concentration;

                             x=0.0366538

Then, round the results to 2 significant figure;

  • [SO_4^2^-] = x = 0.037 mol. L ^-^1
  • [H^+] = x = 0.037 mol. L ^-^1
  • [HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1

Learn more about concentration here:

brainly.com/question/14469428

#SPJ4

3 0
2 years ago
What would be the mass of 3 moles of water molecules?
ankoles [38]

Answer:

\boxed {\boxed {\sf A. \ 54 \ grams }}

Explanation:

To convert from moles to grams, we must use the molar mass.

Recall that water's molecular formula is H₂O. It contains hydrogen and oxygen. Look up the two elements masses on the Periodic Table.

  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 15.999 g/mol

Now, use these masses to find water's mass. The subscript of 2 tells us there are 2 atoms of hydrogen, so we multiply hydrogen's mass by 2 and add oxygen's.

  • H₂O= 2(1.008 g/mol) + 15.999 g/mol = 18.015 g/mol

Use the molar mass as a ratio.

\frac{18.015 \ g \ H_2 O}{ 1 \ mol \ H_2 O}

Multiply by the given number of moles.

3 \ mol \ H_2O*\frac{18.015 \ g \ H_2 O}{ 1 \ mol \ H_2 O}

The moles of water will cancel.

3 *\frac{18.015 \ g \ H_2 O}{ 1 }

3 *{18.015 \ g \ H_2 O}

54.045 \ g \ H_2O

Round to the nearest whole number. The 0 in the tenth place tells us to leave the number as is.

54 \ g \ H_2O

There are about <u>54 grams</u> of water in 3 moles.

7 0
3 years ago
Read 2 more answers
How many liters of oxygen gas (O2) are needed to produce 100 kJ of energy at STP? 2C6H6(I) + 1502(g) —&gt; 12CO2(g)+6H2O(g)+3909
makkiz [27]

Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atmosphere respectively.  

1 mole of every gas occupy volume at STP = 22.4 L

The balanced chemical reaction is:

2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)

3909.9 kJ of of energy is produced by  = 15\times 22.4=336L

100 kJ of oxygen gas are needed to produce = \frac{336}{3909.9}\times 100=8.59L

7 0
3 years ago
What happens when you combine ammonia and formaldehyde?
bija089 [108]

Answer:

The mechanism for the formation of hexamethylenetetraamine predicts the formation of aminomethanol from the addition of ammonia to formaldehyde. This molecule subsequently undergoes unimolecular decomposition to form methanimine and water.

Explanation:

Brainliest please?

5 0
3 years ago
How many times do u have to run back and forth across a football field to be meter
Taya2010 [7]
You would have to run 100 kilometers across it once. Then you will have to run 10 meters across it because a football field is 110 meters according to the NFL’s website
7 0
3 years ago
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