Answer:
K20(s)+H2O(L) -> 2KOH(aq)
Answer:
37.5 mL
Explanation:
To solve this problem we can use the formula:
C₁ = 0.400 M
V₁ = ?
C₂ = 0.150 M
V₂ = 100 mL
So now we <em>solve for V₁</em>:
- 0.400 M * V₁ = 0.150 M * 100 mL
So we need 37.5 mL of 0.400 M CuSO₄(aq) to make 100 mL of 0.150 M CuSO₄(aq). That volume could be measured in the 50 mL buret.
Density is mass over volume. If you put it into a formula it would look like this:
Based on the problem given, you can see that the mass of the aluminum block is 82.0 g and the volume is 12.8 cm3. Just put that into your equation and solve for it:
The answer is then letter C.
Fe(s)+Ca(NO₃)₂(aq)⇒no reaction
<h3>Further explanation</h3>
In voltaic series
Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the element located on the left can push the element on the right in the redox reaction
Reaction
Fe(s)+Ca(NO₃)₂(aq)⇒no reaction
Fe cannot reduce Ca because Ca is more reactive, so the reaction does not occur
On the contrary, this reaction can occur
3Ca(s) + 2Fe(NO₃)₃(aq) = 3Ca(NO₃)₂(aq) + 2Fe(s)