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3 years ago

11

What the three injuries which can happen in the lab when chemicals are used incorrectly?

1 answer:

stepladder [879]3 years ago

7 0

Answer:

Eye injuries,Burns,Respiratory injuries

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Which scientist first attempted to construct a periodic table based on an element's atomic mass? A. Mendeleev B. Newton C. Dalto

Andrew [12]

<span>A. The Russian chemist Dmitri Mendeleev </span>

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3 years ago

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When solutions of barium chloride and lithium sulfate are mixed, the spectator ions in the resulting reaction are?

Pepsi [2]

Barium chloride and lithium sulfate are mixed, barium sulfate and lithium chloride are formed. Barium sulfate is obtained as a white precipitate and lithium chloride as an aqueous solution.

Hope it helped!

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3 years ago

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A student obtains a mixture of the chlorides of two unknown metals, X and Z. The percent by mass of X and the percent by mass of

Hitman42 [59]

Answer:

Molar masses of X and Z

Explanation:

To determine the mole percent of a mixture ( mole percent of unknown metals = number of mole of each of them divided the total of both the unknown salt × 100) since the percent by mass is know; we the molar mass of X and Z

mole = mass given / molar mass

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3 years ago

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Turn on Write equation. What you see is an equation that shows the original uranium atom on the left. The boxes on the right rep

My name is Ann [436]

Answer:

Uranium-238 undergoes alpha decay to form Thorium-234 as daughter product.

Explanation:

Alpha decay is indicative of loss of the equivalents of a helium particle emission. The reaction equation for this reaction is shown below:

$_{92} ^{238} U_{}$ → $_{90} ^{234} Th_{} + _{2} ^{4} He_{}$

I hope this explanation is clear and explanatory.

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4 years ago

An electrochemical cell has the following standard cell notation.

icang [17]

The cell notation is:

$Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)$

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell

in anodic half cell : oxidation takes place [loss of electrons]

in cathodic half cell: reduction takes place [gain of electrons]

1) this is a galvanic cell

2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode

$E^{0}_{Mg}=-2.38V$

$E^{0}_{Ag}=+0.80V$

Therefore

$E^{0}_{cell}=0.80-(-2.38)=+3.18V$

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative

Δ $G^{0}=-nFE^{0}$

As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.

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3 years ago