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e-lub [12.9K]
3 years ago
6

PLEASE HELPname 4 fundamentally different options for cooking a chicken​

Physics
2 answers:
11111nata11111 [884]3 years ago
5 0

Answer:

roasting,

broiling,

pan-broiling,

pan-frying,

grilling.

Explanation:

good luck

Soloha48 [4]3 years ago
4 0

Answer:

Explanation:

1. Stir frying

2. Pan frying

3. Grilling /BBQ

4. Baking/roasting

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Please help me understand this
zloy xaker [14]

Answer: Can't see the photo clearly.

6 0
2 years ago
(f) What do you mean by: (i) 1 J energy (ii) 1 W power​
max2010maxim [7]

Explanation:

Watts are defined as 1 Watt = 1 Joule per second (1W = 1 J/s)

which means that 1 kW = 1000 J/s. A Watt is the amount of energy (in Joules) that an electrical device (such as a light) is burning per second that it's running.

3 0
3 years ago
In this setup how can potential energy be converted into kinetic energy .
d1i1m1o1n [39]

Answer:

If force is applied to cause the motion of the body

Explanation:

In the setup given in this diagram, potential energy can be converted into kinetic energy by applying force on the cart or object to move it down the slope.

Potential energy is the energy due to the position of a body. The body has huge potential energy at its current position.

Kinetic energy is the energy due to the motion of a body.

As the body moves down the slope and its velocity increases, it gains massive kinetic energy.

Down the slope, the kinetic energy increases as the potential energy decreases.

At the bottom of the slope, the potential energy becomes zero and the kinetic energy is at its maximum.

7 0
3 years ago
In a gasoline engine,__<br>energy is converted into kinetic energy.<br><br>is it thermal?​
12345 [234]

It might be possible to argue for "thermal", but it would be tough.

A much better answer is "chemical" ... the engine runs on the chemical energy stored in the gasoline.

5 0
3 years ago
Read 2 more answers
A 8.34 × 103-kg lunar landing craft is about to touch down on the surface of the moon, where the acceleration due to gravity is
Mnenie [13.5K]

Answer:

21870.3156 N

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 1.6 m/s²

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-18.2^2}{2\times 162}\\\Rightarrow a=-1.02234\ m/s^2

The acceleration of the craft should be 1.02234 m/s²

F=ma\\\Rightarrow F=8.34\times 10^3\times 1.02234\\\Rightarrow F=8526.3156\ N

Weight of the craft

W=mg\\\Rightarrow W=8.34\times 10^3\times 1.6\\\Rightarrow W=13344\ N

Thrust

F_t=F+W\\\Rightarrow F_t=8526.3156+13344\\\Rightarrow F_t=21870.3156\ N

The thrust needed to reduce the velocity to zero at the instant when the craft touches the lunar surface is 21870.3156 N

3 0
4 years ago
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