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kobusy [5.1K]
3 years ago
6

Help pretty please jdjsmsjsj

Chemistry
2 answers:
Aleks04 [339]3 years ago
8 0

Answer:

less metallic

Explanation:

BabaBlast [244]3 years ago
6 0

Answer:

D; Decrease in atomic mass.

Explanation:

I looked at the periodic table.

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Which of the following correctly described a compound
victus00 [196]

Answer:

We need the options to answer.

Explanation:

N/A

5 0
3 years ago
A) A cat dish has a mass of 1975 g and a volume of 7500ml. What is the overall density of the cat dish? B) find the maximum mass
maxonik [38]
What's the answer? It asked to be 20 characters long so just writing this.
5 0
3 years ago
What volume of nitrogen (n2) would be completely consumed in the reaction with 30.80 g of
Shtirlitz [24]

The answer is 285.33g nitrogen would be completely consumed in the reaction with 30.80 g of hydrogen gas.

<h3>What is a mole ?</h3>

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

Write a balanced equation.

Calculate the moles of H₂ in 30.8 g.

Calculate the moles of N₂ required to react with H₂.

Calculate the mass of N₂.

Calculate the initial mass of N₂.

Start with a balanced equation.

N₂ + 3H₂ --> 2NH₃

Calculate the moles of H₂ in 30.8 g.

n = m/M; where n = moles, m = mass, and M = molar mass.

M(H₂) = 1.008 g/mol

n(H₂) = (30.8 g)/(1.008 g/mol) = 30.56 mol H₂

Calculate the moles of N₂ required to react with 30.56 mol H₂ , using the mole ratio between H₂ and N₂ in the balanced equation.

30.56 mol H₂ × 1 mol N₂/3 mol H₂ = 10.18 mol N₂

Calculate the mass of N₂ in 10.18 mol.

m = n × M

M(N₂) = 2 × 14.007 g/mol N = 28.014 g/mol N₂

m(N₂) = 10.18 mol × 28.014 g/mol = 285.33g N₂

Therefore 285.33g nitrogen would be completely consumed in the reaction with 30.80 g of hydrogen gas.

To know more about mole

brainly.com/question/26416088

#SPJ1

5 0
2 years ago
Consider two solutions: one formed by adding 10.0 grams of glucose (C6H12O6) to 1.0 L of water
timofeeve [1]

Answer:

Explanation:

Lowering of vapour pressure of solvent is proportional to number of moles   of solute dissolved in it per litre .

No of moles of glucose dissolved

= mass dissolved / molecular weight of glucose

= 10 / 180

= .055  moles.

No of moles of sucrose dissolved = 10 / 342

= .029 moles.

So reduction in vapour pressure will be lower of  solution dissolving sucrose . It is so because , no of moles of solute dissolved in it is low.  

8 0
3 years ago
List the common elements with allotropes.​
Ivahew [28]
Carbon , oxygen , sulfur , tin , and phosphorus .
6 0
3 years ago
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