Argon-40 because it is the isotope with the closest mass to the atomic mass of the element. Making it more stable than the others allowing it to be the most abundant in nature.
To solve this problem, all we have to do it to make use of
the principle of ratio and proportion. We are given the following ratio:
1 part Chlorine / 10 parts Water
Now to determine the amount of chlorine needed for 15
ounces of water, all we have to do is to use proportion. Let us say that the
amount of Chlorine needed is x, therefore:
1 part Chlorine / 10 parts Water = x / 15 ounces Water
so,
1 / 10 = x / 15
Therefore calculating for x:
x = 15 / 10
<span>x = 1.5 ounces of Chlorine</span>
Contains only Carbon and Hydrogen.
(3) CH3CH3
1) State the balanced chemical equation
Na3 PO4 + 3 AgNO3 → 3NaNO3 + Ag3 PO4
sodium phosphate silver nitrate sodium nitrate silver phosphate
2) State the molar ratios
1 mol Na3PO4 : 3 mol AgNO3 : 3 mol NaNO3 : 1 mol Ag3 PO4
3) As you see 3 moles of Silver Nitrate react with 1 mol of Na3 PO4, then you will need.
The you need to use the molar ratio 1:3 to calculate the number of moles of sodium phosphate
1 mol Ag NO3 * [ 1 mol Na3 PO4 / 3 mol Ag NO3] = 0.33 mol Na3 PO4
Answer: 0.33 mol sodium phosphate
Answer:
4.76×10¯⁵ cm
Explanation:
We'll begin by converting 476 nm to m. This can be obtained as follow:
1 nm = 1×10¯⁹ m
Therefore,
476 nm = 476 nm × 1×10¯⁹ m / 1 nm
476 nm = 4.76×10¯⁷ m
Finally, we shall convert 4.76×10¯⁷ m to cm. This can be obtained as follow:
1 m = 100 cm
Therefore,
4.76×10¯⁷ m = 4.76×10¯⁷ m × 100 cm / 1 m
4.76×10¯⁷ m = 4.76×10¯⁵ cm
Thus,
476 nm = 4.76×10¯⁵ cm
