w = instantaneous angular speed = 1.25 rad/s
r = radius = 4.65 m
α = angular acceleration = 0.745 rad/s²
centripetal acceleration is given as
= rw²
= (4.65 ) (1.25)² = 7.27 m/s²
tangential acceleration is given as
= rα
=4.65 x 0.745 = 3.46 m/s²
angle is given as
= 64.5 deg
Answer:
1.35m
Explanation:
At the highest point of the jump, the vertical speed of the skier should be 0. So the 13m/s speed is horizontal, this speed stays the same from the jumping point to the highest point. The 14m/s speed at jumping point is the combination of both vertical and horizontal speeds.
The vertical speed at the jumping point can be computed:
When the skier jumps to the its potential energy is converted to kinetic energy:
where m is the skier mass and h is the vertical distance traveled, is the vertical velocity at jumping point, and h is the highest point.
Let g = 10m/s2
We can divide both sides of the equation by m: