Answer:
32s
Explanation:
We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

and the police car distance:

Since they both travel the same distance x, we can equal both formulas and solve for t:

Two solutions exist to the equation; the first one being 
The second solution will be:

This result allows us to confirm that the police car will take 32s to catch up to the speeder
Answer:
1.73 m/s²
Explanation:
Given:
Δx = 250 m
v₀ = 0 m/s
t = 17 s
Find: a
Δx = v₀ t + ½ at²
250 m = (0 m/s) (17 s) + ½ a (17 s)²
a = 1.73 m/s²
Answer:
Velocity = 0.0001389 m/s
Explanation:
Given that the
Distance covered = 1 metre
Time taken = 2 hours
Convert the hour to second
1 hour = 60 × 60 = 3600
2 hours = 2 × 3600 = 7200
What is the velocity of a worm moving 1 meter in 2 hours to the East?
Velocity can be referred as speed.
Velocity = distance/ time
Velocity = 1/7200
Velocity = 0.0001389 m/s