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dsp73
3 years ago
15

Steel wool turns from a gray color to a reddish color after it gets wet and then sits on a counter. Is this a sign of a chemical

or physical change? PLEASE ANSWER ASAP!
Chemistry
1 answer:
jekas [21]3 years ago
5 0

Answer: Steel wool turns from a gray color to a reddish color after it gets wet and then sits on a counter is a sign of chemical change.

Explanation:

A change that brings change in chemical composition of a substance is called a chemical change.

For example, Steel wool turns from a gray color to a reddish color after it gets wet and then sits on a counter is a chemical change.

This is because steel wool is mostly made up of iron and when iron becomes wet then in the presence of air it gets oxidized and therefore, it gets corroded.

This corrosion appears as reddish color of steel wool and it represents a chemical change has occurred in the steel wool.

Thus, we can conclude that steel wool turns from a gray color to a reddish color after it gets wet and then sits on a counter is a sign of chemical change.

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Measure and pour a half cup (8 tablespoons) of tap water into the small container. Measure and record the temperature of the wat
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Answer:

around 50–55 degrees.

Explanation:

I believe this would be it because chemical reactions haven't happened yet. This is the usual tempurature for tap water.  :)

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3 years ago
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How does an atom-88 become a strontium ion with a +2 charge?
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Strontium atom loses 2 electrons to become an ion with 2 electrons lesser than its atom. Your answer is C.

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3 years ago
If you travel 7.5 km and walk for 1.5 h, what is your average speed? <br> Show your work?
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3 years ago
A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?
Leno4ka [110]

Answer : The volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K

Putting values in above equation, we get:

\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L

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3 0
3 years ago
What is the mass of 5.119 102 molecules of copper sulfate<br> (CuSO4)?
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Answer:

Mass = 135.66 ×10⁻²¹ g

Explanation:

Given data:

Number of molecules of CuSO₄= 5.119×10²

Mass of CuSO₄= ?

Solution:

The given problem will solve by using Avogadro number.

1 mole contain 6.022×10²³ molecules

5.119×10² molecules ×1 mol / 6.022×10²³ molecules

0.85×10⁻²¹ mol

Mass in grams:

Mass = number of moles × molar mass

Mass = 0.85×10⁻²¹ mol × 159.6 g/mol

Mass = 135.66 ×10⁻²¹ g

7 0
3 years ago
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